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What is the output when the following code is executed?

```java
int x = -7;
x++;
x++;
x--;
System.out.println(x);
```

Sagot :

GinnyAnsweridn
Sure! Let's analyze and solve the problem step by step.

1. Initial Value Assignment:
- Start with the initial value of [tex]\( x \)[/tex]. Here, [tex]\( x \)[/tex] is initially assigned the value [tex]\(-7\)[/tex]:
[tex]\[ x = -7 \][/tex]

2. First Operation [tex]\( x++ \)[/tex]:
- The [tex]\( x++ \)[/tex] operation increments [tex]\( x \)[/tex] by 1. So, after this operation:
[tex]\[ x = -7 + 1 = -6 \][/tex]
- Now, [tex]\( x \)[/tex] is [tex]\(-6\)[/tex].

3. Second Operation [tex]\( x++ \)[/tex]:
- Again, [tex]\( x++ \)[/tex] increments [tex]\( x \)[/tex] by 1. So, after this operation:
[tex]\[ x = -6 + 1 = -5 \][/tex]
- Now, [tex]\( x \)[/tex] is [tex]\(-5\)[/tex].

4. Third Operation [tex]\( x-- \)[/tex]:
- The [tex]\( x-- \)[/tex] operation decrements [tex]\( x \)[/tex] by 1. So, after this operation:
[tex]\[ x = -5 - 1 = -6 \][/tex]
- Now, [tex]\( x \)[/tex] is [tex]\(-6\)[/tex].

5. Output the Value of [tex]\( x \)[/tex]:
- Finally, when we print the value of [tex]\( x \)[/tex], the output will be:
[tex]\[ \text{System.out.println}(x) \implies -6 \][/tex]

So, the output when the code is executed is:
[tex]\[ -6 \][/tex]
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