IDNLearn.com: Your one-stop platform for getting reliable answers to any question. Our platform offers reliable and detailed answers, ensuring you have the information you need.
Sagot :
Sure! Let's go step by step to solve this problem.
### Given:
a) The sum of two numbers is 10 and the sum of their squares is 68.
#### (i) If one of the numbers is [tex]\( x \)[/tex], write the other number in terms of [tex]\( x \)[/tex].
If one of the numbers is [tex]\( x \)[/tex], then the other number can be written as [tex]\( 10 - x \)[/tex], since the sum of the two numbers is 10.
#### (ii) Find the numbers.
We need two equations here:
1. The sum of the numbers:
[tex]\[ x + (10 - x) = 10 \][/tex]
2. The sum of their squares:
[tex]\[ x^2 + (10 - x)^2 = 68 \][/tex]
Let's simplify the second equation step-by-step:
[tex]\[ x^2 + (10 - x)^2 = 68 \][/tex]
Expand [tex]\( (10 - x)^2 \)[/tex]:
[tex]\[ (10 - x)^2 = 100 - 20x + x^2 \][/tex]
So the equation becomes:
[tex]\[ x^2 + 100 - 20x + x^2 = 68 \][/tex]
Combine like terms:
[tex]\[ 2x^2 - 20x + 100 = 68 \][/tex]
Subtract 68 from both sides to set the equation to zero:
[tex]\[ 2x^2 - 20x + 32 = 0 \][/tex]
This is a quadratic equation [tex]\( 2x^2 - 20x + 32 = 0 \)[/tex].
To solve the quadratic equation, we use the quadratic formula [tex]\( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} \)[/tex], where [tex]\( a = 2 \)[/tex], [tex]\( b = -20 \)[/tex], and [tex]\( c = 32 \)[/tex].
Calculate the discriminant:
[tex]\[ b^2 - 4ac = (-20)^2 - 4 \cdot 2 \cdot 32 = 400 - 256 = 144 \][/tex]
Now find the roots:
[tex]\[ x = \frac{{20 \pm \sqrt{144}}}{4} \][/tex]
[tex]\[ x = \frac{{20 \pm 12}}{4} \][/tex]
So, we get two solutions:
[tex]\[ x_1 = \frac{{20 + 12}}{4} = \frac{32}{4} = 8 \][/tex]
[tex]\[ x_2 = \frac{{20 - 12}}{4} = \frac{8}{4} = 2 \][/tex]
The numbers are 8 and 2.
#### (iii) Find the ratio of the sum to the product of the numbers.
The sum of the numbers is:
[tex]\[ 8 + 2 = 10 \][/tex]
The product of the numbers is:
[tex]\[ 8 \times 2 = 16 \][/tex]
The ratio of the sum to the product is:
[tex]\[ \frac{{\text{sum of the numbers}}}{{\text{product of the numbers}}} = \frac{10}{16} = 0.625 \][/tex]
So, the ratio of the sum to the product of the numbers is [tex]\( 0.625 \)[/tex].
### Summary:
1. The numbers are 8 and 2.
2. The ratio of the sum to the product of the numbers is [tex]\( 0.625 \)[/tex].
### Given:
a) The sum of two numbers is 10 and the sum of their squares is 68.
#### (i) If one of the numbers is [tex]\( x \)[/tex], write the other number in terms of [tex]\( x \)[/tex].
If one of the numbers is [tex]\( x \)[/tex], then the other number can be written as [tex]\( 10 - x \)[/tex], since the sum of the two numbers is 10.
#### (ii) Find the numbers.
We need two equations here:
1. The sum of the numbers:
[tex]\[ x + (10 - x) = 10 \][/tex]
2. The sum of their squares:
[tex]\[ x^2 + (10 - x)^2 = 68 \][/tex]
Let's simplify the second equation step-by-step:
[tex]\[ x^2 + (10 - x)^2 = 68 \][/tex]
Expand [tex]\( (10 - x)^2 \)[/tex]:
[tex]\[ (10 - x)^2 = 100 - 20x + x^2 \][/tex]
So the equation becomes:
[tex]\[ x^2 + 100 - 20x + x^2 = 68 \][/tex]
Combine like terms:
[tex]\[ 2x^2 - 20x + 100 = 68 \][/tex]
Subtract 68 from both sides to set the equation to zero:
[tex]\[ 2x^2 - 20x + 32 = 0 \][/tex]
This is a quadratic equation [tex]\( 2x^2 - 20x + 32 = 0 \)[/tex].
To solve the quadratic equation, we use the quadratic formula [tex]\( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} \)[/tex], where [tex]\( a = 2 \)[/tex], [tex]\( b = -20 \)[/tex], and [tex]\( c = 32 \)[/tex].
Calculate the discriminant:
[tex]\[ b^2 - 4ac = (-20)^2 - 4 \cdot 2 \cdot 32 = 400 - 256 = 144 \][/tex]
Now find the roots:
[tex]\[ x = \frac{{20 \pm \sqrt{144}}}{4} \][/tex]
[tex]\[ x = \frac{{20 \pm 12}}{4} \][/tex]
So, we get two solutions:
[tex]\[ x_1 = \frac{{20 + 12}}{4} = \frac{32}{4} = 8 \][/tex]
[tex]\[ x_2 = \frac{{20 - 12}}{4} = \frac{8}{4} = 2 \][/tex]
The numbers are 8 and 2.
#### (iii) Find the ratio of the sum to the product of the numbers.
The sum of the numbers is:
[tex]\[ 8 + 2 = 10 \][/tex]
The product of the numbers is:
[tex]\[ 8 \times 2 = 16 \][/tex]
The ratio of the sum to the product is:
[tex]\[ \frac{{\text{sum of the numbers}}}{{\text{product of the numbers}}} = \frac{10}{16} = 0.625 \][/tex]
So, the ratio of the sum to the product of the numbers is [tex]\( 0.625 \)[/tex].
### Summary:
1. The numbers are 8 and 2.
2. The ratio of the sum to the product of the numbers is [tex]\( 0.625 \)[/tex].
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and see you next time for more reliable information.