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Which of the following is the additive inverse of [tex]\frac{1}{2}[/tex]?

A. [tex]\frac{1}{2}[/tex]
B. 2
C. [tex]-2[/tex]


Sagot :

To determine the additive inverse of [tex]\(\frac{1}{2}\)[/tex], we need to understand the concept of an additive inverse. The additive inverse of a number is a value that, when added to the original number, results in zero.

Let's denote the original number as [tex]\(a\)[/tex]. The additive inverse of [tex]\(a\)[/tex] is the number [tex]\(b\)[/tex] such that:

[tex]\[ a + b = 0 \][/tex]

Given [tex]\(a = \frac{1}{2}\)[/tex], we need to find [tex]\(b\)[/tex] that satisfies:

[tex]\[ \frac{1}{2} + b = 0 \][/tex]

To isolate [tex]\(b\)[/tex], subtract [tex]\(\frac{1}{2}\)[/tex] from both sides:

[tex]\[ b = 0 - \frac{1}{2} \][/tex]

[tex]\[ b = -\frac{1}{2} \][/tex]

Therefore, the additive inverse of [tex]\(\frac{1}{2}\)[/tex] is [tex]\(-\frac{1}{2}\)[/tex].

Let's review the provided options to identify which [tex]\(-\frac{1}{2}\)[/tex] corresponds to:

- [tex]\(\frac{1}{2}\)[/tex]
- [tex]\(2\)[/tex]
- [tex]\(-2\)[/tex]

None of the given options directly represent [tex]\(-\frac{1}{2}\)[/tex].

Therefore, the additive inverse of [tex]\(\frac{1}{2}\)[/tex] is [tex]\(-\frac{1}{2}\)[/tex]. Since negative [tex]\(\frac{1}{2}\)[/tex] isn't listed among the multiple choice options you provided, it implies the correct choice should have been included as:

- [tex]\(-\frac{1}{2}\)[/tex]

The correct additive inverse is:
[tex]\[-0.5\][/tex]

But none of the listed choices matches this exactly.
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