To evaluate [tex]\(\log_2 32\)[/tex], we need to determine the exponent [tex]\(x\)[/tex] such that [tex]\(2^x = 32\)[/tex].
Let's start by expressing 32 as a power of 2:
[tex]\[
32 = 2 \times 2 \times 2 \times 2 \times 2 = 2^5
\][/tex]
This shows that 32 can be written as [tex]\(2^5\)[/tex]. Therefore, the exponent [tex]\(x\)[/tex] that satisfies the equation [tex]\(2^x = 32\)[/tex] is 5.
Hence, [tex]\(\log_2 32 = 5\)[/tex].
The correct answer is:
C. 5
