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Sagot :
To compare the mean and median of the fundraiser totals, let's first outline the steps involved in calculating both and then determine the relationship between them.
### Step-by-Step Solution:
1. List the Fundraiser Totals:
The totals for the last five years are: 896, 925, 880, 963, and 914.
2. Calculate the Mean (Average):
The mean is calculated by summing all the totals and then dividing by the number of values.
[tex]\[ \text{Mean Total} = \frac{896 + 925 + 880 + 963 + 914}{5} = \frac{4578}{5} = 915.6 \][/tex]
3. Calculate the Median:
The median is the middle value when the totals are ordered from smallest to largest. When we order the given totals, we get: 880, 896, 914, 925, 963. Since there are five values, the median is the third value in the ordered list.
[tex]\[ \text{Median Total} = 914 \][/tex]
4. Determine the Difference Between the Mean and the Median:
[tex]\[ \text{Difference} = \text{Mean} - \text{Median} = 915.6 - 914 = 1.6 \][/tex]
From this calculation, we see that the mean (915.6) is greater than the median (914) by \[tex]$1.6. ### Conclusion: The correct statement is: - The mean is $[/tex]1.60$ greater than the median.
### Step-by-Step Solution:
1. List the Fundraiser Totals:
The totals for the last five years are: 896, 925, 880, 963, and 914.
2. Calculate the Mean (Average):
The mean is calculated by summing all the totals and then dividing by the number of values.
[tex]\[ \text{Mean Total} = \frac{896 + 925 + 880 + 963 + 914}{5} = \frac{4578}{5} = 915.6 \][/tex]
3. Calculate the Median:
The median is the middle value when the totals are ordered from smallest to largest. When we order the given totals, we get: 880, 896, 914, 925, 963. Since there are five values, the median is the third value in the ordered list.
[tex]\[ \text{Median Total} = 914 \][/tex]
4. Determine the Difference Between the Mean and the Median:
[tex]\[ \text{Difference} = \text{Mean} - \text{Median} = 915.6 - 914 = 1.6 \][/tex]
From this calculation, we see that the mean (915.6) is greater than the median (914) by \[tex]$1.6. ### Conclusion: The correct statement is: - The mean is $[/tex]1.60$ greater than the median.
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