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In a class of students, the following data table summarizes how many students have a brother or a sister. What is the probability that a student has a sister given that they have a brother?

\begin{tabular}{|c|c|c|}
\hline
& \begin{tabular}{c}
Has a \\
brother
\end{tabular}
& \begin{tabular}{c}
Does not \\
have a \\
brother
\end{tabular} \\
\hline
Has a sister & 6 & 8 \\
\hline
\begin{tabular}{c}
Does not \\
have a sister
\end{tabular} & 2 & 10 \\
\hline
\end{tabular}


Sagot :

To determine the probability that a student has a sister given that they have a brother, we need to use the concept of conditional probability. Conditional probability is calculated as follows:

[tex]\[ P(A | B) = \frac{P(A \cap B)}{P(B)} \][/tex]

Where:
- [tex]\( P(A | B) \)[/tex] is the probability that event [tex]\( A \)[/tex] occurs given that event [tex]\( B \)[/tex] has occurred.
- [tex]\( P(A \cap B) \)[/tex] is the probability that both events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] occur.
- [tex]\( P(B) \)[/tex] is the probability that event [tex]\( B \)[/tex] occurs.

In this context:
- Event [tex]\( A \)[/tex] is "the student has a sister."
- Event [tex]\( B \)[/tex] is "the student has a brother."

From the given data, we can extract the following values:
- Number of students who have both a brother and a sister ( [tex]\( P(A \cap B) \)[/tex] ) = 6
- Number of students who have a brother, with or without a sister ( [tex]\( P(B) \)[/tex] ) = 6 (both brother and sister) + 2 (brother but no sister) = 8

Now, we can calculate the conditional probability that a student has a sister given that they have a brother:

[tex]\[ P(\text{sister} | \text{brother}) = \frac{\text{Number of students who have both a brother and a sister}}{\text{Total number of students who have a brother}} = \frac{6}{8} = 0.75 \][/tex]

So, the probability that a student has a sister given that they have a brother is [tex]\( 0.75 \)[/tex] or 75%.