IDNLearn.com provides a platform for sharing and gaining valuable knowledge. Find reliable solutions to your questions quickly and easily with help from our experienced experts.
Sagot :
To determine which fractions are equivalent to [tex]\(\frac{4}{12}\)[/tex], we need to simplify [tex]\(\frac{4}{12}\)[/tex] and identify other fractions that simplify to the same form.
First, let’s simplify [tex]\(\frac{4}{12}\)[/tex]:
1. Find the greatest common divisor (GCD) of the numerator (4) and the denominator (12).
2. The GCD of 4 and 12 is 4.
3. Divide both the numerator and the denominator by their GCD:
[tex]\[ \frac{4 \div 4}{12 \div 4} = \frac{1}{3} \][/tex]
So, the simplest form of [tex]\(\frac{4}{12}\)[/tex] is [tex]\(\frac{1}{3}\)[/tex].
Now, let's simplify each of the given fractions to see if they are equivalent to [tex]\(\frac{1}{3}\)[/tex]:
1. [tex]\(\frac{2}{10}\)[/tex]:
- Find the GCD of 2 and 10, which is 2.
- Simplify: [tex]\(\frac{2 \div 2}{10 \div 2} = \frac{1}{5}\)[/tex]
- [tex]\(\frac{1}{5}\)[/tex] is not equal to [tex]\(\frac{1}{3}\)[/tex].
2. [tex]\(\frac{2}{6}\)[/tex]:
- Find the GCD of 2 and 6, which is 2.
- Simplify: [tex]\(\frac{2 \div 2}{6 \div 2} = \frac{1}{3}\)[/tex]
- [tex]\(\frac{1}{3}\)[/tex] is equal to [tex]\(\frac{1}{3}\)[/tex].
3. [tex]\(\frac{1}{6}\)[/tex]:
- The numerator and denominator are already simplified, and there’s no common divisor other than 1.
- [tex]\(\frac{1}{6}\)[/tex] is already in its simplest form and is not equal to [tex]\(\frac{1}{3}\)[/tex].
4. [tex]\(\frac{1}{9}\)[/tex]:
- The numerator and denominator are already simplified, and there’s no common divisor other than 1.
- [tex]\(\frac{1}{9}\)[/tex] is already in its simplest form and is not equal to [tex]\(\frac{1}{3}\)[/tex].
5. [tex]\(\frac{1}{3}\)[/tex]:
- The numerator and denominator are already simplified, and there’s no common divisor other than 1.
- [tex]\(\frac{1}{3}\)[/tex] is equal to [tex]\(\frac{1}{3}\)[/tex].
After simplifying all given fractions, we find that the fractions equivalent to [tex]\(\frac{4}{12}\)[/tex] are:
[tex]\[ \boxed{\frac{2}{6} \text{ and } \frac{1}{3}} \][/tex]
First, let’s simplify [tex]\(\frac{4}{12}\)[/tex]:
1. Find the greatest common divisor (GCD) of the numerator (4) and the denominator (12).
2. The GCD of 4 and 12 is 4.
3. Divide both the numerator and the denominator by their GCD:
[tex]\[ \frac{4 \div 4}{12 \div 4} = \frac{1}{3} \][/tex]
So, the simplest form of [tex]\(\frac{4}{12}\)[/tex] is [tex]\(\frac{1}{3}\)[/tex].
Now, let's simplify each of the given fractions to see if they are equivalent to [tex]\(\frac{1}{3}\)[/tex]:
1. [tex]\(\frac{2}{10}\)[/tex]:
- Find the GCD of 2 and 10, which is 2.
- Simplify: [tex]\(\frac{2 \div 2}{10 \div 2} = \frac{1}{5}\)[/tex]
- [tex]\(\frac{1}{5}\)[/tex] is not equal to [tex]\(\frac{1}{3}\)[/tex].
2. [tex]\(\frac{2}{6}\)[/tex]:
- Find the GCD of 2 and 6, which is 2.
- Simplify: [tex]\(\frac{2 \div 2}{6 \div 2} = \frac{1}{3}\)[/tex]
- [tex]\(\frac{1}{3}\)[/tex] is equal to [tex]\(\frac{1}{3}\)[/tex].
3. [tex]\(\frac{1}{6}\)[/tex]:
- The numerator and denominator are already simplified, and there’s no common divisor other than 1.
- [tex]\(\frac{1}{6}\)[/tex] is already in its simplest form and is not equal to [tex]\(\frac{1}{3}\)[/tex].
4. [tex]\(\frac{1}{9}\)[/tex]:
- The numerator and denominator are already simplified, and there’s no common divisor other than 1.
- [tex]\(\frac{1}{9}\)[/tex] is already in its simplest form and is not equal to [tex]\(\frac{1}{3}\)[/tex].
5. [tex]\(\frac{1}{3}\)[/tex]:
- The numerator and denominator are already simplified, and there’s no common divisor other than 1.
- [tex]\(\frac{1}{3}\)[/tex] is equal to [tex]\(\frac{1}{3}\)[/tex].
After simplifying all given fractions, we find that the fractions equivalent to [tex]\(\frac{4}{12}\)[/tex] are:
[tex]\[ \boxed{\frac{2}{6} \text{ and } \frac{1}{3}} \][/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.