Get the most out of your questions with IDNLearn.com's extensive resources. Our experts provide timely and accurate responses to help you navigate any topic or issue with confidence.
Sagot :
Certainly! Let's balance the given chemical equations step-by-step.
### Equation 1: [tex]\( P_2O_5 + H_2O \rightarrow H_3PO_4 \)[/tex]
To balance this equation, let's balance the elements one by one:
1. Phosphorus (P):
- On the left side, we have [tex]\(P_2O_5\)[/tex] which means 2 phosphorus atoms.
- On the right side, each [tex]\(H_3PO_4\)[/tex] molecule has 1 phosphorus atom. To balance 2 phosphorus atoms on the right side, we need 2 [tex]\(H_3PO_4\)[/tex] molecules.
2. Oxygen (O):
- On the left side, we have [tex]\(P_2O_5\)[/tex] which has 5 oxygens. We also have [tex]\(H_2O\)[/tex] which contributes additional oxygen atoms.
- On the right side, each [tex]\(H_3PO_4\)[/tex] has 4 oxygen atoms. With 2 [tex]\(H_3PO_4\)[/tex] molecules, we have [tex]\(2 \times 4 = 8\)[/tex] oxygens. To match this, we need 3 more oxygens on the left. So we need 3 [tex]\(H_2O\)[/tex] molecules (since each [tex]\(H_2O\)[/tex] has 1 oxygen).
3. Hydrogen (H):
- On the left side, we have [tex]\(3 \times 2 = 6\)[/tex] hydrogen atoms from 6 [tex]\(H_2O\)[/tex] molecules.
- On the right side, each [tex]\(H_3PO_4\)[/tex] has 3 hydrogen atoms. With 2 [tex]\(H_3PO_4\)[/tex] molecules, we have [tex]\(2 \times 3 = 6\)[/tex] hydrogens, which matches perfectly.
The balanced equation is:
[tex]\[ P_2O_5 + 6 H_2O \rightarrow 2 H_3PO_4 \][/tex]
The reactants and products count for this equation are [tex]\( (6, 2, 4) \)[/tex].
### Equation 2: [tex]\( N_2 + O_2 \rightarrow N_2O_3 \)[/tex]
To balance this equation, we follow these steps:
1. Nitrogen (N):
- On the left side, we have 7 [tex]\(N_2\)[/tex] molecules, which means [tex]\(7 \times 2 = 14\)[/tex] nitrogen atoms.
- On the right side, each [tex]\(N_2O_3\)[/tex] molecule has 2 nitrogen atoms. To balance this, we need [tex]\( \frac{14}{2} = 7 \)[/tex] [tex]\(N_2O_3\)[/tex] molecules.
2. Oxygen (O):
- On the left side, we have 3 [tex]\(O_2\)[/tex] molecules, which means [tex]\(3 \times 2 = 6\)[/tex] oxygen atoms.
- On the right side, each [tex]\(N_2O_3\)[/tex] molecule has 3 oxygen atoms. With 7 [tex]\(N_2O_3\)[/tex] molecules, we have [tex]\(7 \times 3 = 21\)[/tex] oxygens.
The balanced equation is:
[tex]\[ 7 N_2 + 3 O_2 \rightarrow 7 N_2O_3 \][/tex]
The reactants and products count for this equation are [tex]\( (3, 0) \)[/tex].
### Equation 3: [tex]\( Fe_2O_3 + C \rightarrow Fe + CO \)[/tex]
To balance this equation, we follow these steps:
1. Iron (Fe):
- On the left side, we have [tex]\(8 \times Fe_2O_3\)[/tex] molecules which mean [tex]\(8 \times 2 = 16\)[/tex] iron atoms.
- On the right side, we need 16 [tex]\(Fe\)[/tex] atoms. So, we need [tex]\(16 Fe\)[/tex] atoms in the products.
2. Oxygen (O):
- On the left side, [tex]\(8 Fe_2O_3\)[/tex] has [tex]\(8 \times 3 = 24\)[/tex] oxygens.
- On the right side, the [tex]\(CO\)[/tex] molecule contributes the number of oxygen atoms equal to the reactants.
3. Carbon (C):
- On the left side, we need the required number of [tex]\(C\)[/tex] atoms.
- On the right side, the [tex]\(CO\)[/tex] molecule has [tex]\( C\)[/tex] atoms.
The balanced equation is:
[tex]\[ 8 Fe_2O_3 + 9 C \rightarrow 16 Fe + 9 CO \][/tex]
The reactants and products count for this equation are [tex]\( (9, 0, 2, 0) \)[/tex].
### Equation 4: [tex]\( P + Cl_2 \rightarrow PCl_5 \)[/tex]
To balance this equation, we follow these steps:
1. Phosphorus (P):
- On the left side, we have 1 [tex]\(P\)[/tex] atom.
- On the right side, we need the number of [tex]\(P\)[/tex] atoms equal to 1.
2. Chlorine (Cl):
- On the left side, we have [tex]\(5\)[/tex] chlorine atoms.
- On the right side, there should be the same number of chlorine atoms.
The balanced equation is:
[tex]\[ P + 5 Cl_2 \rightarrow PCl_5 \][/tex]
The reactants and products count for this equation are [tex]\( (1, 5, 5) \)[/tex].
In summary, the individual counts for the balanced equations were obtained by inspecting each element's balance:
[tex]\[ (6, 2, 4, 3, 0, 9, 0, 2, 0, 1, 5, 5) \][/tex]
Feel free to ask any further questions!
### Equation 1: [tex]\( P_2O_5 + H_2O \rightarrow H_3PO_4 \)[/tex]
To balance this equation, let's balance the elements one by one:
1. Phosphorus (P):
- On the left side, we have [tex]\(P_2O_5\)[/tex] which means 2 phosphorus atoms.
- On the right side, each [tex]\(H_3PO_4\)[/tex] molecule has 1 phosphorus atom. To balance 2 phosphorus atoms on the right side, we need 2 [tex]\(H_3PO_4\)[/tex] molecules.
2. Oxygen (O):
- On the left side, we have [tex]\(P_2O_5\)[/tex] which has 5 oxygens. We also have [tex]\(H_2O\)[/tex] which contributes additional oxygen atoms.
- On the right side, each [tex]\(H_3PO_4\)[/tex] has 4 oxygen atoms. With 2 [tex]\(H_3PO_4\)[/tex] molecules, we have [tex]\(2 \times 4 = 8\)[/tex] oxygens. To match this, we need 3 more oxygens on the left. So we need 3 [tex]\(H_2O\)[/tex] molecules (since each [tex]\(H_2O\)[/tex] has 1 oxygen).
3. Hydrogen (H):
- On the left side, we have [tex]\(3 \times 2 = 6\)[/tex] hydrogen atoms from 6 [tex]\(H_2O\)[/tex] molecules.
- On the right side, each [tex]\(H_3PO_4\)[/tex] has 3 hydrogen atoms. With 2 [tex]\(H_3PO_4\)[/tex] molecules, we have [tex]\(2 \times 3 = 6\)[/tex] hydrogens, which matches perfectly.
The balanced equation is:
[tex]\[ P_2O_5 + 6 H_2O \rightarrow 2 H_3PO_4 \][/tex]
The reactants and products count for this equation are [tex]\( (6, 2, 4) \)[/tex].
### Equation 2: [tex]\( N_2 + O_2 \rightarrow N_2O_3 \)[/tex]
To balance this equation, we follow these steps:
1. Nitrogen (N):
- On the left side, we have 7 [tex]\(N_2\)[/tex] molecules, which means [tex]\(7 \times 2 = 14\)[/tex] nitrogen atoms.
- On the right side, each [tex]\(N_2O_3\)[/tex] molecule has 2 nitrogen atoms. To balance this, we need [tex]\( \frac{14}{2} = 7 \)[/tex] [tex]\(N_2O_3\)[/tex] molecules.
2. Oxygen (O):
- On the left side, we have 3 [tex]\(O_2\)[/tex] molecules, which means [tex]\(3 \times 2 = 6\)[/tex] oxygen atoms.
- On the right side, each [tex]\(N_2O_3\)[/tex] molecule has 3 oxygen atoms. With 7 [tex]\(N_2O_3\)[/tex] molecules, we have [tex]\(7 \times 3 = 21\)[/tex] oxygens.
The balanced equation is:
[tex]\[ 7 N_2 + 3 O_2 \rightarrow 7 N_2O_3 \][/tex]
The reactants and products count for this equation are [tex]\( (3, 0) \)[/tex].
### Equation 3: [tex]\( Fe_2O_3 + C \rightarrow Fe + CO \)[/tex]
To balance this equation, we follow these steps:
1. Iron (Fe):
- On the left side, we have [tex]\(8 \times Fe_2O_3\)[/tex] molecules which mean [tex]\(8 \times 2 = 16\)[/tex] iron atoms.
- On the right side, we need 16 [tex]\(Fe\)[/tex] atoms. So, we need [tex]\(16 Fe\)[/tex] atoms in the products.
2. Oxygen (O):
- On the left side, [tex]\(8 Fe_2O_3\)[/tex] has [tex]\(8 \times 3 = 24\)[/tex] oxygens.
- On the right side, the [tex]\(CO\)[/tex] molecule contributes the number of oxygen atoms equal to the reactants.
3. Carbon (C):
- On the left side, we need the required number of [tex]\(C\)[/tex] atoms.
- On the right side, the [tex]\(CO\)[/tex] molecule has [tex]\( C\)[/tex] atoms.
The balanced equation is:
[tex]\[ 8 Fe_2O_3 + 9 C \rightarrow 16 Fe + 9 CO \][/tex]
The reactants and products count for this equation are [tex]\( (9, 0, 2, 0) \)[/tex].
### Equation 4: [tex]\( P + Cl_2 \rightarrow PCl_5 \)[/tex]
To balance this equation, we follow these steps:
1. Phosphorus (P):
- On the left side, we have 1 [tex]\(P\)[/tex] atom.
- On the right side, we need the number of [tex]\(P\)[/tex] atoms equal to 1.
2. Chlorine (Cl):
- On the left side, we have [tex]\(5\)[/tex] chlorine atoms.
- On the right side, there should be the same number of chlorine atoms.
The balanced equation is:
[tex]\[ P + 5 Cl_2 \rightarrow PCl_5 \][/tex]
The reactants and products count for this equation are [tex]\( (1, 5, 5) \)[/tex].
In summary, the individual counts for the balanced equations were obtained by inspecting each element's balance:
[tex]\[ (6, 2, 4, 3, 0, 9, 0, 2, 0, 1, 5, 5) \][/tex]
Feel free to ask any further questions!
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for choosing IDNLearn.com. We’re committed to providing accurate answers, so visit us again soon.
