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Sagot :
To divide [tex]\( 7 \)[/tex] by [tex]\( 2 \)[/tex] and find the quotient and remainder, follow these steps:
1. Determine how many times the divisor (2) fits into the dividend (7) without exceeding it:
- [tex]\( 2 \times 3 = 6 \)[/tex] (which is the highest multiple of 2 that does not exceed 7).
- Since [tex]\( 2 \times 4 = 8 \)[/tex] exceeds 7, we use 3 as the quotient.
2. Subtract the product obtained in step 1 from the dividend to find the remainder:
- [tex]\( 7 - 6 = 1 \)[/tex]
So, when 7 is divided by 2:
- The quotient is [tex]\( 3 \)[/tex] (because [tex]\( 2 \)[/tex] fits into [tex]\( 7 \)[/tex] three times).
- The remainder is [tex]\( 1 \)[/tex] (left over after subtracting [tex]\( 6 \)[/tex] from [tex]\( 7 \)[/tex]).
Therefore, [tex]\( 7 \div 2 \)[/tex] results in a quotient of 3 and a remainder of 1.
Hence, the answer to the division problem is:
[tex]\[ 7 \div 2 = 3 \, R1 \][/tex]
1. Determine how many times the divisor (2) fits into the dividend (7) without exceeding it:
- [tex]\( 2 \times 3 = 6 \)[/tex] (which is the highest multiple of 2 that does not exceed 7).
- Since [tex]\( 2 \times 4 = 8 \)[/tex] exceeds 7, we use 3 as the quotient.
2. Subtract the product obtained in step 1 from the dividend to find the remainder:
- [tex]\( 7 - 6 = 1 \)[/tex]
So, when 7 is divided by 2:
- The quotient is [tex]\( 3 \)[/tex] (because [tex]\( 2 \)[/tex] fits into [tex]\( 7 \)[/tex] three times).
- The remainder is [tex]\( 1 \)[/tex] (left over after subtracting [tex]\( 6 \)[/tex] from [tex]\( 7 \)[/tex]).
Therefore, [tex]\( 7 \div 2 \)[/tex] results in a quotient of 3 and a remainder of 1.
Hence, the answer to the division problem is:
[tex]\[ 7 \div 2 = 3 \, R1 \][/tex]
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