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Which of the following is the explicit rule for a geometric sequence defined by a recursive formula of [tex]a_n = 13 a_{n-1}[/tex] for which the first term is 7?

A. [tex]a_n = 13 \cdot 7^{n-1}[/tex]

B. [tex]a_n = 7 \cdot 13^{n+1}[/tex]

C. [tex]a_n = 7 \cdot 13^{n-1}[/tex]

D. [tex]a_n = 13 \cdot 7^{n+1}[/tex]


Sagot :

To find the explicit rule of a geometric sequence given a recursive formula and the first term, we can follow these steps:

1. Identify the first term ([tex]\(a_1\)[/tex]) and the common ratio ([tex]\(r\)[/tex]):

- The first term [tex]\(a_1\)[/tex] is given as 7.
- The recursive formula [tex]\(a_n = 13 \cdot a_{n-1}\)[/tex] indicates that the common ratio [tex]\(r\)[/tex] is 13.

2. Recall the general form for the explicit rule of a geometric sequence:

The n-th term of a geometric sequence can be expressed as:
[tex]\[ a_n = a_1 \cdot r^{n-1} \][/tex]
where [tex]\(a_1\)[/tex] is the first term and [tex]\(r\)[/tex] is the common ratio.

3. Substitute the given first term and common ratio into the general form:

- First term [tex]\(a_1 = 7\)[/tex]
- Common ratio [tex]\(r = 13\)[/tex]

Therefore, the explicit formula becomes:
[tex]\[ a_n = 7 \cdot 13^{n-1} \][/tex]

4. Match this explicit formula to the provided options:

Let's compare the derived formula [tex]\(a_n = 7 \cdot 13^{n-1}\)[/tex] with the given options:

- Option A: [tex]\(a_n = 13 \cdot 7^{n-1}\)[/tex]
- Option B: [tex]\(a_n = 7 \cdot 13^{n+1}\)[/tex]
- Option C: [tex]\(a_n = 7 \cdot 13^{n-1}\)[/tex]
- Option D: [tex]\(a_n = 13 \cdot 7^{n+1}\)[/tex]

We see that Option C matches exactly with our derived explicit rule.

Therefore, the correct answer is:

C. [tex]\(a_n = 7 \cdot 13^{n-1}\)[/tex]