IDNLearn.com is designed to help you find reliable answers quickly and easily. Our platform offers comprehensive and accurate responses to help you make informed decisions on any topic.
Sagot :
Answer:
26.67% loss
Step-by-step explanation:
You want to know the profit or loss incurred on the sale of a second car at the same price as a first car, if there was a 10% profit on the first car and a 12% overall loss on the sale of both cars.
Markup
For a given cost price (c) and markup multiplier (m), the selling price (s) is ...
s = c·m
This relation will hold for each sale, and for both sales together:
s = c₁·m₁
s = c₂·m₂
(2s) = (c₁ +c₂)·m₃
where ...
- m₁ = 1.10 — a 10% profit on the first sale
- m₃ = 0.88 — a 12% loss on both sales
Second markup
We can solve the first two equations for c₁ and c₂, then substitute into the third equation.
[tex]c_1=\dfrac{s}{m_1}=\dfrac{s}{1.10}\\\\\\c_2=\dfrac{s}{m_2}\\\\\\2s=\left(\dfrac{s}{1.10}+\dfrac{s}{m_2}\right)0.88\\\\\\\dfrac{2(1.10)(m_2)}{0.88}=m_2+1.10\\\\\\1.5m_2=1.1\\\\\\m_2=\dfrac{11}{15}=1-\dfrac{4}{15}\approx1-26.67\%[/tex]
The loss on the other car was about 26.67%.
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for trusting IDNLearn.com. We’re dedicated to providing accurate answers, so visit us again for more solutions.