Find solutions to your problems with the help of IDNLearn.com's expert community. Our experts are ready to provide prompt and detailed answers to any questions you may have.
Sagot :
To find the dimensions of Planck's constant [tex]\( h \)[/tex] from the given equation [tex]\(\lambda = \frac{h}{P}\)[/tex], we will use dimensional analysis. Let's break this down step-by-step:
### Step 1: Understand the Given Equation
The given equation is:
[tex]\[ \lambda = \frac{h}{P} \][/tex]
where:
- [tex]\(\lambda\)[/tex] is the wavelength.
- [tex]\( h \)[/tex] is Planck's constant.
- [tex]\( P \)[/tex] is the momentum.
### Step 2: Determine Dimensions of Known Quantities
We start by determining the dimensions of [tex]\(\lambda\)[/tex] and [tex]\( P \)[/tex].
#### Dimensions of Wavelength ([tex]\(\lambda\)[/tex]):
The wavelength is a measure of length. Therefore, its dimension is:
[tex]\[ [\lambda] = [L] \][/tex]
#### Dimensions of Momentum ([tex]\(P\)[/tex]):
Momentum [tex]\( P \)[/tex] is defined as the product of mass and velocity. Hence, its dimensions are:
[tex]\[ [P] = [M][L][T]^{-1} \][/tex]
where:
- [tex]\( [M] \)[/tex] represents mass.
- [tex]\( [L] \)[/tex] represents length.
- [tex]\( [T] \)[/tex] represents time.
### Step 3: Use Dimensional Analysis
Using the equation [tex]\(\lambda = \frac{h}{P}\)[/tex], we isolate [tex]\( h \)[/tex]:
[tex]\[ h = \lambda \cdot P \][/tex]
### Step 4: Find the Dimensions of Planck's Constant ([tex]\( h \)[/tex])
Substitute the dimensions of [tex]\(\lambda\)[/tex] and [tex]\( P \)[/tex] into the equation:
[tex]\[ [h] = [\lambda] \cdot [P] \][/tex]
Using the dimensions we identified earlier:
[tex]\[ [h] = [L] \cdot [M][L][T]^{-1} \][/tex]
### Step 5: Simplify the Dimensions
Simplify the expression by combining like terms:
[tex]\[ [h] = [M][L] \cdot [L][T]^{-1} \][/tex]
This further reduces to:
[tex]\[ [h] = [M][L]^2[T]^{-1} \][/tex]
### Conclusion
The dimensions of Planck's constant [tex]\( h \)[/tex] are:
[tex]\[ [h] = [M][L]^2[T]^{-1] \][/tex]
### Step 1: Understand the Given Equation
The given equation is:
[tex]\[ \lambda = \frac{h}{P} \][/tex]
where:
- [tex]\(\lambda\)[/tex] is the wavelength.
- [tex]\( h \)[/tex] is Planck's constant.
- [tex]\( P \)[/tex] is the momentum.
### Step 2: Determine Dimensions of Known Quantities
We start by determining the dimensions of [tex]\(\lambda\)[/tex] and [tex]\( P \)[/tex].
#### Dimensions of Wavelength ([tex]\(\lambda\)[/tex]):
The wavelength is a measure of length. Therefore, its dimension is:
[tex]\[ [\lambda] = [L] \][/tex]
#### Dimensions of Momentum ([tex]\(P\)[/tex]):
Momentum [tex]\( P \)[/tex] is defined as the product of mass and velocity. Hence, its dimensions are:
[tex]\[ [P] = [M][L][T]^{-1} \][/tex]
where:
- [tex]\( [M] \)[/tex] represents mass.
- [tex]\( [L] \)[/tex] represents length.
- [tex]\( [T] \)[/tex] represents time.
### Step 3: Use Dimensional Analysis
Using the equation [tex]\(\lambda = \frac{h}{P}\)[/tex], we isolate [tex]\( h \)[/tex]:
[tex]\[ h = \lambda \cdot P \][/tex]
### Step 4: Find the Dimensions of Planck's Constant ([tex]\( h \)[/tex])
Substitute the dimensions of [tex]\(\lambda\)[/tex] and [tex]\( P \)[/tex] into the equation:
[tex]\[ [h] = [\lambda] \cdot [P] \][/tex]
Using the dimensions we identified earlier:
[tex]\[ [h] = [L] \cdot [M][L][T]^{-1} \][/tex]
### Step 5: Simplify the Dimensions
Simplify the expression by combining like terms:
[tex]\[ [h] = [M][L] \cdot [L][T]^{-1} \][/tex]
This further reduces to:
[tex]\[ [h] = [M][L]^2[T]^{-1} \][/tex]
### Conclusion
The dimensions of Planck's constant [tex]\( h \)[/tex] are:
[tex]\[ [h] = [M][L]^2[T]^{-1] \][/tex]
Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.