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During Van-Mahotsava, Class VII A and VII B planted trees in their school premises. Section A planted 5 more than thrice the number of trees planted by Section B. Together they planted 221 trees. Find the number of trees planted by Section A.

Sagot :

Sure, let's solve the problem step-by-step.

Let's denote the number of trees planted by Section B as [tex]\( x \)[/tex].

According to the problem, Section A planted 5 more than thrice the number of trees planted by Section B. So, the number of trees planted by Section A can be expressed as:
[tex]\[ 3x + 5 \][/tex]

Together, Sections A and B planted 221 trees. Therefore, we can set up the following equation:
[tex]\[ x + (3x + 5) = 221 \][/tex]

Now, simplify the equation:
[tex]\[ x + 3x + 5 = 221 \][/tex]
[tex]\[ 4x + 5 = 221 \][/tex]

Next, isolate the variable [tex]\( x \)[/tex] by subtracting 5 from both sides of the equation:
[tex]\[ 4x = 216 \][/tex]

Then, solve for [tex]\( x \)[/tex] by dividing both sides by 4:
[tex]\[ x = 54 \][/tex]

Hence, Section B planted [tex]\( x = 54 \)[/tex] trees.

To find the number of trees planted by Section A, substitute [tex]\( x = 54 \)[/tex] into the expression [tex]\( 3x + 5 \)[/tex]:
[tex]\[ 3(54) + 5 = 162 + 5 = 167 \][/tex]

Therefore, Section A planted 167 trees.