Get the answers you've been looking for with the help of IDNLearn.com's expert community. Our experts provide accurate and detailed responses to help you navigate any topic or issue with confidence.
Sagot :
We will determine whether each of the given equations is quadratic or not. A quadratic equation is a polynomial equation of degree 2, which generally takes the form [tex]\(ax^2 + bx + c = 0\)[/tex], where [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex] are constants, and [tex]\(a \neq 0\)[/tex].
Let's analyze each equation step-by-step:
1. [tex]\((x+3)+8=0\)[/tex]
Simplifying, we get:
[tex]\(x + 11 = 0\)[/tex], which is a linear equation (degree 1), not a quadratic.
2. [tex]\(x^2 + 10 = 3x\)[/tex]
Rearrange to form a standard polynomial:
[tex]\(x^2 - 3x + 10 = 0\)[/tex], which is a quadratic equation (degree 2).
3. [tex]\(2(x+3)^2=0\)[/tex]
Expanding the equation:
[tex]\(2(x^2 + 6x + 9) = 0\)[/tex]
Simplifies to:
[tex]\(2x^2 + 12x + 18 = 0\)[/tex], which is a quadratic equation (degree 2).
4. [tex]\((x-2)^2 + 5=0\)[/tex]
Expanding the equation:
[tex]\((x^2 - 4x + 4) + 5 = 0\)[/tex]
Simplifies to:
[tex]\(x^2 - 4x + 9 = 0\)[/tex], which is a quadratic equation (degree 2).
5. [tex]\(x^2 - 2x + 5=0\)[/tex]
This is already in the standard form:
[tex]\(x^2 - 2x + 5 = 0\)[/tex], which is a quadratic equation (degree 2).
6. [tex]\(0 = x(x+3)(x-5)\)[/tex]
Expanding the equation:
[tex]\(0 = x(x^2 - 2x - 15)\)[/tex]
Simplifies to:
[tex]\(x^3 - 2x^2 - 15x = 0\)[/tex], which is a cubic equation (degree 3), not a quadratic.
7. [tex]\((x-1)^2=0\)[/tex]
Expanding the equation:
[tex]\(x^2 - 2x + 1 = 0\)[/tex], which is a quadratic equation (degree 2).
8. [tex]\((x+1)(x-2) = 3\)[/tex]
Expanding the left-hand side:
[tex]\(x^2 - x - 2 = 3\)[/tex]
Rearrange to form a standard polynomial:
[tex]\(x^2 - x - 5 = 0\)[/tex], which is a quadratic equation (degree 2).
9. [tex]\(2x^4 + x - 1 = 0\)[/tex]
This is already in polynomial form, but the highest power is:
Degree 4, which is not quadratic (degree 4).
10. [tex]\(\frac{9x}{7} + 7x - 1 = 0\)[/tex]
Combining the terms:
[tex]\(\left(\frac{9}{7} + 7\right)x - 1 = 0\)[/tex]
Just simplifies the coefficients of x, but the degree remains:
Degree 1, which is not quadratic (degree 1).
11. [tex]\(\left[x(x-2)^2 - 3\right] = 7\)[/tex]
Equivalently:
[tex]\(x(x^2 - 4x + 4) - 3 = 7\)[/tex]
Simplifying:
[tex]\(x^3 - 4x^2 + 4x - 3 = 7\)[/tex]
Rearranging:
[tex]\(x^3 - 4x^2 + 4x - 10 = 0\)[/tex], which is a cubic equation (degree 3), not a quadratic.
12. [tex]\(\frac{x^3 + 2}{5} - 6 = 0\)[/tex]
Multiplying by 5 to clear the fraction:
[tex]\(x^3 + 2 - 30 = 0\)[/tex]
Simplifies to:
[tex]\(x^3 - 28 = 0\)[/tex], which is a cubic equation (degree 3), not a quadratic.
Summary:
Quadratic equations from the list are:
- [tex]\(2. x^2 - 3x + 10 = 0\)[/tex]
- [tex]\(3. 2x^2 + 12x + 18 = 0\)[/tex]
- [tex]\(4. x^2 - 4x + 9 = 0\)[/tex]
- [tex]\(5. x^2 - 2x + 5 = 0\)[/tex]
- [tex]\(7. x^2 - 2x + 1 = 0\)[/tex]
- [tex]\(8. x^2 - x - 5 = 0\)[/tex]
Equations that are not quadratic:
- [tex]\(1. x + 11 = 0\)[/tex]
- [tex]\(6. x^3 - 2x^2 - 15x = 0\)[/tex]
- [tex]\(9. 2x^4 + x - 1 = 0\)[/tex]
- [tex]\(10. \left(\frac{9}{7} + 7\right)x - 1 = 0\)[/tex]
- [tex]\(11. x^3 - 4x^2 + 4x - 10 = 0\)[/tex]
- [tex]\(12. x^3 - 28 = 0\)[/tex]
Let's analyze each equation step-by-step:
1. [tex]\((x+3)+8=0\)[/tex]
Simplifying, we get:
[tex]\(x + 11 = 0\)[/tex], which is a linear equation (degree 1), not a quadratic.
2. [tex]\(x^2 + 10 = 3x\)[/tex]
Rearrange to form a standard polynomial:
[tex]\(x^2 - 3x + 10 = 0\)[/tex], which is a quadratic equation (degree 2).
3. [tex]\(2(x+3)^2=0\)[/tex]
Expanding the equation:
[tex]\(2(x^2 + 6x + 9) = 0\)[/tex]
Simplifies to:
[tex]\(2x^2 + 12x + 18 = 0\)[/tex], which is a quadratic equation (degree 2).
4. [tex]\((x-2)^2 + 5=0\)[/tex]
Expanding the equation:
[tex]\((x^2 - 4x + 4) + 5 = 0\)[/tex]
Simplifies to:
[tex]\(x^2 - 4x + 9 = 0\)[/tex], which is a quadratic equation (degree 2).
5. [tex]\(x^2 - 2x + 5=0\)[/tex]
This is already in the standard form:
[tex]\(x^2 - 2x + 5 = 0\)[/tex], which is a quadratic equation (degree 2).
6. [tex]\(0 = x(x+3)(x-5)\)[/tex]
Expanding the equation:
[tex]\(0 = x(x^2 - 2x - 15)\)[/tex]
Simplifies to:
[tex]\(x^3 - 2x^2 - 15x = 0\)[/tex], which is a cubic equation (degree 3), not a quadratic.
7. [tex]\((x-1)^2=0\)[/tex]
Expanding the equation:
[tex]\(x^2 - 2x + 1 = 0\)[/tex], which is a quadratic equation (degree 2).
8. [tex]\((x+1)(x-2) = 3\)[/tex]
Expanding the left-hand side:
[tex]\(x^2 - x - 2 = 3\)[/tex]
Rearrange to form a standard polynomial:
[tex]\(x^2 - x - 5 = 0\)[/tex], which is a quadratic equation (degree 2).
9. [tex]\(2x^4 + x - 1 = 0\)[/tex]
This is already in polynomial form, but the highest power is:
Degree 4, which is not quadratic (degree 4).
10. [tex]\(\frac{9x}{7} + 7x - 1 = 0\)[/tex]
Combining the terms:
[tex]\(\left(\frac{9}{7} + 7\right)x - 1 = 0\)[/tex]
Just simplifies the coefficients of x, but the degree remains:
Degree 1, which is not quadratic (degree 1).
11. [tex]\(\left[x(x-2)^2 - 3\right] = 7\)[/tex]
Equivalently:
[tex]\(x(x^2 - 4x + 4) - 3 = 7\)[/tex]
Simplifying:
[tex]\(x^3 - 4x^2 + 4x - 3 = 7\)[/tex]
Rearranging:
[tex]\(x^3 - 4x^2 + 4x - 10 = 0\)[/tex], which is a cubic equation (degree 3), not a quadratic.
12. [tex]\(\frac{x^3 + 2}{5} - 6 = 0\)[/tex]
Multiplying by 5 to clear the fraction:
[tex]\(x^3 + 2 - 30 = 0\)[/tex]
Simplifies to:
[tex]\(x^3 - 28 = 0\)[/tex], which is a cubic equation (degree 3), not a quadratic.
Summary:
Quadratic equations from the list are:
- [tex]\(2. x^2 - 3x + 10 = 0\)[/tex]
- [tex]\(3. 2x^2 + 12x + 18 = 0\)[/tex]
- [tex]\(4. x^2 - 4x + 9 = 0\)[/tex]
- [tex]\(5. x^2 - 2x + 5 = 0\)[/tex]
- [tex]\(7. x^2 - 2x + 1 = 0\)[/tex]
- [tex]\(8. x^2 - x - 5 = 0\)[/tex]
Equations that are not quadratic:
- [tex]\(1. x + 11 = 0\)[/tex]
- [tex]\(6. x^3 - 2x^2 - 15x = 0\)[/tex]
- [tex]\(9. 2x^4 + x - 1 = 0\)[/tex]
- [tex]\(10. \left(\frac{9}{7} + 7\right)x - 1 = 0\)[/tex]
- [tex]\(11. x^3 - 4x^2 + 4x - 10 = 0\)[/tex]
- [tex]\(12. x^3 - 28 = 0\)[/tex]
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Your questions deserve reliable answers. Thanks for visiting IDNLearn.com, and see you again soon for more helpful information.