Get detailed and reliable answers to your questions with IDNLearn.com. Join our community to receive prompt and reliable responses to your questions from knowledgeable professionals.
Sagot :
Let's solve the given equation step by step:
[tex]\[ \frac{(1+\cos A)^2 - (1-\cos A)^2}{\sin^2 A} = 4 \operatorname{cosec} A \cdot \cot A \][/tex]
First, let's simplify the expression on the left-hand side.
### Step 1: Expand the Numerator
We start with the numerator [tex]\((1 + \cos A)^2 - (1 - \cos A)^2\)[/tex].
Using the algebraic identity [tex]\((a + b)^2 - (a - b)^2 = 4ab\)[/tex]:
[tex]\[ (1 + \cos A)^2 = 1 + 2 \cos A + \cos^2 A \][/tex]
[tex]\[ (1 - \cos A)^2 = 1 - 2 \cos A + \cos^2 A \][/tex]
Subtracting these two expanded forms:
[tex]\[ (1 + \cos A)^2 - (1 - \cos A)^2 = (1 + 2 \cos A + \cos^2 A) - (1 - 2 \cos A + \cos^2 A) \][/tex]
[tex]\[ = 1 + 2 \cos A + \cos^2 A - 1 + 2 \cos A - \cos^2 A \][/tex]
[tex]\[ = (1 - 1) + (2 \cos A + 2 \cos A) + (\cos^2 A - \cos^2 A) \][/tex]
[tex]\[ = 4 \cos A \][/tex]
### Step 2: Form the Fraction
Now, place the result back in the original fraction:
[tex]\[ \frac{4 \cos A}{\sin^2 A} \][/tex]
### Step 3: Work with Trigonometric Identities on the Right-hand Side
The given right-hand side is [tex]\(4 \operatorname{cosec} A \cdot \cot A\)[/tex].
Recall the trigonometric identities:
[tex]\[ \operatorname{cosec} A = \frac{1}{\sin A} \][/tex]
[tex]\[ \cot A = \frac{\cos A}{\sin A} \][/tex]
So,
[tex]\[ 4 \operatorname{cosec} A \cdot \cot A = 4 \left(\frac{1}{\sin A}\right) \left(\frac{\cos A}{\sin A}\right) \][/tex]
### Step 4: Simplify the Right-hand Side
Multiply these fractions:
[tex]\[ 4 \cdot \frac{1}{\sin A} \cdot \frac{\cos A}{\sin A} = 4 \cdot \frac{\cos A}{\sin^2 A} \][/tex]
### Step 5: Comparison
The left-hand side simplifies to:
[tex]\[ \frac{4 \cos A}{\sin^2 A} \][/tex]
The right-hand side simplifies to:
[tex]\[ \frac{4 \cos A}{\sin^2 A} \][/tex]
Both sides are equal. Thus, we can conclude:
[tex]\[ \frac{(1+\cos A)^2 - (1-\cos A)^2}{\sin^2 A} = 4 \operatorname{cosec} A \cdot \cot A \][/tex]
And thereby, the trigonometric identity holds true.
[tex]\[ \frac{(1+\cos A)^2 - (1-\cos A)^2}{\sin^2 A} = 4 \operatorname{cosec} A \cdot \cot A \][/tex]
First, let's simplify the expression on the left-hand side.
### Step 1: Expand the Numerator
We start with the numerator [tex]\((1 + \cos A)^2 - (1 - \cos A)^2\)[/tex].
Using the algebraic identity [tex]\((a + b)^2 - (a - b)^2 = 4ab\)[/tex]:
[tex]\[ (1 + \cos A)^2 = 1 + 2 \cos A + \cos^2 A \][/tex]
[tex]\[ (1 - \cos A)^2 = 1 - 2 \cos A + \cos^2 A \][/tex]
Subtracting these two expanded forms:
[tex]\[ (1 + \cos A)^2 - (1 - \cos A)^2 = (1 + 2 \cos A + \cos^2 A) - (1 - 2 \cos A + \cos^2 A) \][/tex]
[tex]\[ = 1 + 2 \cos A + \cos^2 A - 1 + 2 \cos A - \cos^2 A \][/tex]
[tex]\[ = (1 - 1) + (2 \cos A + 2 \cos A) + (\cos^2 A - \cos^2 A) \][/tex]
[tex]\[ = 4 \cos A \][/tex]
### Step 2: Form the Fraction
Now, place the result back in the original fraction:
[tex]\[ \frac{4 \cos A}{\sin^2 A} \][/tex]
### Step 3: Work with Trigonometric Identities on the Right-hand Side
The given right-hand side is [tex]\(4 \operatorname{cosec} A \cdot \cot A\)[/tex].
Recall the trigonometric identities:
[tex]\[ \operatorname{cosec} A = \frac{1}{\sin A} \][/tex]
[tex]\[ \cot A = \frac{\cos A}{\sin A} \][/tex]
So,
[tex]\[ 4 \operatorname{cosec} A \cdot \cot A = 4 \left(\frac{1}{\sin A}\right) \left(\frac{\cos A}{\sin A}\right) \][/tex]
### Step 4: Simplify the Right-hand Side
Multiply these fractions:
[tex]\[ 4 \cdot \frac{1}{\sin A} \cdot \frac{\cos A}{\sin A} = 4 \cdot \frac{\cos A}{\sin^2 A} \][/tex]
### Step 5: Comparison
The left-hand side simplifies to:
[tex]\[ \frac{4 \cos A}{\sin^2 A} \][/tex]
The right-hand side simplifies to:
[tex]\[ \frac{4 \cos A}{\sin^2 A} \][/tex]
Both sides are equal. Thus, we can conclude:
[tex]\[ \frac{(1+\cos A)^2 - (1-\cos A)^2}{\sin^2 A} = 4 \operatorname{cosec} A \cdot \cot A \][/tex]
And thereby, the trigonometric identity holds true.
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for choosing IDNLearn.com. We’re here to provide reliable answers, so please visit us again for more solutions.