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What is the maximum cold-holding temperature allowed for sliced watermelon?

A. [tex]$32^{\circ} F \left(0^{\circ} C \right)$[/tex]
B. [tex]$38^{\circ} F \left(3^{\circ} C \right)$[/tex]
C. [tex]$41^{\circ} F \left(5^{\circ} C \right)$[/tex]
D. [tex]$45^{\circ} F \left(7^{\circ} C \right)$[/tex]

Sagot :

GinnyAnsweridn
To determine the maximum cold-holding temperature allowed for sliced watermelon, we need to consider the options provided and see which one matches the regulated standard. Let’s analyze each option:

a. [tex]$32^{\circ} F \left(0^{\circ} C \right)$[/tex]
b. [tex]$38^{\circ} F \left(3^{\circ} C \right)$[/tex]
c. [tex]$41^{\circ} F \left(5^{\circ} C \right)$[/tex]
d. [tex]$45^{\circ} F \left(7^{\circ} C \right)$[/tex]

The correct regulation states that the maximum cold-holding temperature allowed for sliced watermelon is [tex]$41^{\circ} F$[/tex]. This translates to [tex]$5^{\circ} C$[/tex] in the Celsius scale.

Hence, the correct answer is:

c. [tex]$41^{\circ} F \left(5^{\circ} C \right)$[/tex]
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