Ashleenbondidn
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The given equation has been solved in the table:

\begin{tabular}{|c|c|}
\hline Step & Statement \\
\hline 1 & [tex]$\frac{x}{2}-7=-7$[/tex] \\
\hline 2 & [tex]$\frac{x}{2}-7+7=-7+7$[/tex] \\
\hline 3 & [tex]$\frac{x}{2}=0$[/tex] \\
\hline 4 & [tex]$2 \cdot \frac{x}{2}=2 \cdot 0$[/tex] \\
\hline 5 & [tex]$x=0$[/tex] \\
\hline
\end{tabular}

In which step was the subtraction property of equality applied?

A. Step 2

B. Step 3

C. Step 4

D. The subtraction property of equality was not applied to solve this equation.

Sagot :

GinnyAnsweridn
To solve the question, let's examine each step of the given equation and identify where the subtraction property of equality was applied.

Step 1: [tex]\(\frac{x}{2} - 7 = -7\)[/tex]

Step 2: [tex]\(\frac{\pi}{2} - 7 + 7 = -7 + 7\)[/tex]

Step 3: [tex]\(\frac{x}{2} = 0\)[/tex]

Step 4: [tex]\(2 \cdot \frac{\pi}{2} = 2 \cdot 0\)[/tex]

Step 5: [tex]\(x = 0\)[/tex]

Subtraction property of equality states that if you subtract the same number from both sides of an equation, it keeps the equation balanced.

Look closely at Step 2:

[tex]\(\frac{\pi}{2} - 7 + 7 = -7 + 7\)[/tex]

Here, 7 is added to both sides to isolate the term [tex]\(\frac{x}{2}\)[/tex] on one side of the equation. This is the application of the subtraction property of equality because you're essentially adding negative 7 to both sides to isolate the [tex]\( \frac{x}{2} \)[/tex] term.

Therefore, the subtraction property of equality was applied in:
A. Step 2
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