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Hailey is shopping at a department store during a [tex]20\%[/tex] off everything sale. She also has a coupon for [tex]\$5.00[/tex] off the sale amount. Hailey wants to keep her total under [tex]\$6500[/tex] before tax, so she creates this inequality:

[tex]\[0.80x - \$5.00 \leq \$6500\][/tex]

Which inequality represents all possible solutions for [tex]x[/tex]?

A. [tex]x \leq \$75.00[/tex]
B. [tex]x \leq \$76.25[/tex]
C. [tex]x \leq \$86.25[/tex]
D. [tex]x \leq \$87.50[/tex]


Sagot :

To solve for [tex]\( x \)[/tex] in the inequality [tex]\( 0.80x - 5.00 \leq 6500 \)[/tex], let's go through the steps systematically:

1. Start with the given inequality:
[tex]\[ 0.80x - 5.00 \leq 6500 \][/tex]

2. Add [tex]\( 5.00 \)[/tex] to both sides to isolate the term involving [tex]\( x \)[/tex]:
[tex]\[ 0.80x - 5.00 + 5.00 \leq 6500 + 5.00 \][/tex]
Simplifying this, we get:
[tex]\[ 0.80x \leq 6505 \][/tex]

3. Divide both sides of the inequality by [tex]\( 0.80 \)[/tex] to solve for [tex]\( x \)[/tex]:
[tex]\[ x \leq \frac{6505}{0.80} \][/tex]

4. Performing the division on the right side:
[tex]\[ x \leq 8131.25 \][/tex]

So, the correct inequality representing all possible solutions for [tex]\( x \)[/tex] is:
[tex]\[ x \leq 8131.25 \][/tex]

Let's match this result with the given options.

- Option A: [tex]\(x \leq 75.00\)[/tex]
- Option B: [tex]\(x \leq 76.25\)[/tex]
- Option C: [tex]\(x \leq 86.25\)[/tex]
- Option D: [tex]\(x \leq 87.50\)[/tex]

None of these options match our result of [tex]\( x \leq 8131.25 \)[/tex]. Therefore, there must be an error in the options provided as none of them represent the correct solution. The correct inequality, as determined by the steps above, is [tex]\( x \leq 8131.25 \)[/tex].
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