IDNLearn.com is the perfect place to get answers, share knowledge, and learn new things. Get comprehensive answers to all your questions from our network of experienced experts.
Sagot :
Certainly! Let's break down the problem step by step.
First, we have the expression:
[tex]\[ 17 \lim _{x \rightarrow -2} -4x \][/tex]
This expression involves a limit as [tex]\( x \)[/tex] approaches [tex]\(-2\)[/tex].
1. Find the Limit:
We need to determine the limit of the function [tex]\(-4x\)[/tex] as [tex]\( x \)[/tex] approaches [tex]\(-2\)[/tex].
To do this, we substitute [tex]\( x = -2 \)[/tex] into the function [tex]\(-4x\)[/tex]:
[tex]\[ -4(-2) = 8 \][/tex]
Therefore:
[tex]\[ \lim_{x \rightarrow -2} -4x = 8 \][/tex]
2. Multiply the Result by 17:
The original problem has a factor of 17 multiplied by the limit we just found. So we need to take the result from our limit calculation and multiply it by 17:
[tex]\[ 17 \times 8 = 136 \][/tex]
Thus, the final result is:
[tex]\[ 17 \lim _{x \rightarrow -2} -4x = 136 \][/tex]
So, the answer is [tex]\( 136 \)[/tex].
First, we have the expression:
[tex]\[ 17 \lim _{x \rightarrow -2} -4x \][/tex]
This expression involves a limit as [tex]\( x \)[/tex] approaches [tex]\(-2\)[/tex].
1. Find the Limit:
We need to determine the limit of the function [tex]\(-4x\)[/tex] as [tex]\( x \)[/tex] approaches [tex]\(-2\)[/tex].
To do this, we substitute [tex]\( x = -2 \)[/tex] into the function [tex]\(-4x\)[/tex]:
[tex]\[ -4(-2) = 8 \][/tex]
Therefore:
[tex]\[ \lim_{x \rightarrow -2} -4x = 8 \][/tex]
2. Multiply the Result by 17:
The original problem has a factor of 17 multiplied by the limit we just found. So we need to take the result from our limit calculation and multiply it by 17:
[tex]\[ 17 \times 8 = 136 \][/tex]
Thus, the final result is:
[tex]\[ 17 \lim _{x \rightarrow -2} -4x = 136 \][/tex]
So, the answer is [tex]\( 136 \)[/tex].
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. For trustworthy answers, visit IDNLearn.com. Thank you for your visit, and see you next time for more reliable solutions.