Answered

IDNLearn.com: Your one-stop destination for finding reliable answers. Get accurate and detailed answers to your questions from our dedicated community members who are always ready to help.

Write the systematic name of each organic molecule:

\begin{tabular}{|c|c|}
\hline
structure & name \\
\hline
\begin{tabular}{l}
ClCC=C(Cl)Cl
\end{tabular} & \\
\hline
\begin{tabular}{l}
CC(C)=CC(Cl)Cl
\end{tabular} & \\
\hline
\begin{tabular}{l}
CCC=C(C)C
\end{tabular} & \\
\hline
\end{tabular}

Sagot :

GinnyAnsweridn
Let's determine the systematic names of the provided organic molecules.

### Molecule 1: ClCC=C(Cl)Cl
1. Identify the longest carbon chain: The longest continuous chain of carbons is 4 carbons long (butene).
2. Identify the functional groups and substituents:
- There are three chlorine atoms.
- Two double bonds are present in the chain.
3. Number the carbon chain: Number the chain such that the double bond and the substituents get the lowest possible numbers.
- Numbering from the left: C1 has a Cl, C2 has a double bond, C3 has another Cl, and C4 has the third Cl.

Thus, the systematic name for this molecule is 2,3,4-trichlorobut-1-ene.

### Molecule 2: CC(C)=CC(Cl)Cl
1. Identify the longest carbon chain: The longest chain includes the double bond and is 4 carbons long (butene).
2. Identify the functional groups and substituents:
- One chlorine substituent.
- Two methyl groups at C2.
3. Number the carbon chain: Number the chain such that the double bond and substituents get the lowest possible numbers.
- Numbering from the left: On C2, we have two methyl groups and C3 has a chlorine group.

Thus, the systematic name for this molecule is 3-chloro-2,3-dimethylbut-1-ene.

### Molecule 3: CCC=C(C)C
1. Identify the longest carbon chain: The longest continuous chain of carbons is 5 carbons long (pentene).
2. Identify the functional groups and substituents:
- There is a methyl group attached to the chain.
3. Number the carbon chain: Number the chain such that the double bond gets the lowest possible number and the substituents are correctly located.
- Counting from left to right, the double bond starts at C2.
- The methyl group is on C3.

Thus, the systematic name for this molecule is 3-methylpent-1-ene.

### Summary:
| Structure | Name |
|---|---|
| ClCC=C(Cl)Cl | 2,3,4-trichlorobut-1-ene |
| CC(C)=CC(Cl)Cl | 3-chloro-2,3-dimethylbut-1-ene |
| CCC=C(C)C | 3-methylpent-1-ene |
Your engagement is important to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.