Sure, let's solve for the perimeters of the given shapes:
### a. Rectangle with length 5 cm and breadth 4 cm:
For a rectangle, the perimeter [tex]\( P \)[/tex] is calculated using the formula:
[tex]\[ P = 2 \times ( \text{length} + \text{breadth} ) \][/tex]
Plugging in the given values:
[tex]\[ \text{length} = 5 \, \text{cm}, \][/tex]
[tex]\[ \text{breadth} = 4 \, \text{cm}, \][/tex]
The perimeter:
[tex]\[ P = 2 \times (5 + 4) \][/tex]
[tex]\[ P = 2 \times 9 \][/tex]
[tex]\[ P = 18 \, \text{cm} \][/tex]
### b. Square with side 15 cm:
For a square, the perimeter [tex]\( P \)[/tex] is calculated using the formula:
[tex]\[ P = 4 \times \text{side} \][/tex]
Plugging in the given value:
[tex]\[ \text{side} = 15 \, \text{cm}, \][/tex]
The perimeter:
[tex]\[ P = 4 \times 15 \][/tex]
[tex]\[ P = 60 \, \text{cm} \][/tex]
### c. Regular hexagon with side 7.2 cm:
For a regular hexagon, the perimeter [tex]\( P \)[/tex] is calculated using the formula:
[tex]\[ P = 6 \times \text{side} \][/tex]
Plugging in the given value:
[tex]\[ \text{side} = 7.2 \, \text{cm}, \][/tex]
The perimeter:
[tex]\[ P = 6 \times 7.2 \][/tex]
[tex]\[ P = 43.2 \, \text{cm} \][/tex]
### d. Equilateral triangle with side 5 cm:
For an equilateral triangle, the perimeter [tex]\( P \)[/tex] is calculated using the formula:
[tex]\[ P = 3 \times \text{side} \][/tex]
Plugging in the given value:
[tex]\[ \text{side} = 5 \, \text{cm}, \][/tex]
The perimeter:
[tex]\[ P = 3 \times 5 \][/tex]
[tex]\[ P = 15 \, \text{cm} \][/tex]
So, the perimeters are:
- Rectangle: [tex]\( 18 \, \text{cm} \)[/tex]
- Square: [tex]\( 60 \, \text{cm} \)[/tex]
- Regular hexagon: [tex]\( 43.2 \, \text{cm} \)[/tex]
- Equilateral triangle: [tex]\( 15 \, \text{cm} \)[/tex]
