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When 4 times a Numbers is increased by 40, the answer is the same as when 100 is dedecreased by the number. I anduve number

Sagot :

Step-by-step explanation:

Let's solve this problem step by step.

You have a number, let's call it \( x \). The problem states:

1. **Four times a number increased by 40:** This can be written as \( 4x + 40 \).

2. **The answer is the same as when 100 is decreased by the number:** This can be written as \( 100 - x \).

According to the problem, these two expressions are equal:

\[

4x + 40 = 100 - x

\]

Now, solve for \( x \):

First, add \( x \) to both sides to eliminate \( -x \) on the right:

\[

4x + x + 40 = 100

\]

This simplifies to:

\[

5x + 40 = 100

\]

Next, subtract 40 from both sides:

\[

5x = 60

\]

Finally, divide by 5:

\[

x = 12

\]

So, the number is \( x = 12 \).

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