IDNLearn.com: Your trusted platform for finding reliable answers. Join our platform to receive prompt and accurate responses from experienced professionals in various fields.
Sagot :
First, given the quadratic equation [tex]\( y = -2x^2 - 9x + 9 \)[/tex], we need to find the [tex]\( x \)[/tex]-intercepts, where the graph of the equation crosses the x-axis. The [tex]\( x \)[/tex]-intercepts occur where [tex]\( y = 0 \)[/tex].
So, we set the equation to zero:
[tex]\[ -2x^2 - 9x + 9 = 0 \][/tex]
We can solve this quadratic equation either using the quadratic formula [tex]\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)[/tex] or graphing calculator methods.
### Method 1: Using the CALC-Zero Feature of a Graphing Calculator
1. Enter the Equation:
- Enter [tex]\( y = -2x^2 - 9x + 9 \)[/tex] into the graphing calculator.
2. Graph the Equation:
- Graph the equation to visualize where it crosses the x-axis.
3. Find the Zeros:
- Use the `CALC` menu to select the `Zero` feature.
- For the first intercept, move the cursor near where the graph crosses the x-axis (right intercept) and follow the prompts to find the zero.
- For the second intercept, move the cursor near the other crossing (left intercept) and find the zero.
### Method 2: Using the CALC-Intersect Feature of a Graphing Calculator
1. Enter the Equations:
- Enter [tex]\( Y_1 = -2x^2 - 9x + 9 \)[/tex] into your graphing calculator.
- Enter [tex]\( Y_2 = 0 \)[/tex] (which is simply the x-axis).
2. Graph the Equations:
- Graph both [tex]\( Y_1 \)[/tex] and [tex]\( Y_2 \)[/tex] on the same set of axes.
3. Find the Intersection Points:
- Use the `CALC` menu to select the `Intersect` feature.
- For the first intercept (right intercept), move the cursor near the intersection point on the right and follow the prompts to determine the x-coordinate of the intersection.
- For the second intercept (left intercept), move the cursor near the intersection point on the left and find the x-coordinate.
After using one of the methods, we find the x-intercepts are approximately:
- [tex]\( x = 0.842 \)[/tex]
- [tex]\( x = -5.342 \)[/tex]
### Solution:
The [tex]\( x \)[/tex]-intercepts, ordered with the larger value first, are:
[tex]\[ (0.842, 0) \][/tex]
[tex]\[ (-5.342, 0) \][/tex]
So, we set the equation to zero:
[tex]\[ -2x^2 - 9x + 9 = 0 \][/tex]
We can solve this quadratic equation either using the quadratic formula [tex]\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)[/tex] or graphing calculator methods.
### Method 1: Using the CALC-Zero Feature of a Graphing Calculator
1. Enter the Equation:
- Enter [tex]\( y = -2x^2 - 9x + 9 \)[/tex] into the graphing calculator.
2. Graph the Equation:
- Graph the equation to visualize where it crosses the x-axis.
3. Find the Zeros:
- Use the `CALC` menu to select the `Zero` feature.
- For the first intercept, move the cursor near where the graph crosses the x-axis (right intercept) and follow the prompts to find the zero.
- For the second intercept, move the cursor near the other crossing (left intercept) and find the zero.
### Method 2: Using the CALC-Intersect Feature of a Graphing Calculator
1. Enter the Equations:
- Enter [tex]\( Y_1 = -2x^2 - 9x + 9 \)[/tex] into your graphing calculator.
- Enter [tex]\( Y_2 = 0 \)[/tex] (which is simply the x-axis).
2. Graph the Equations:
- Graph both [tex]\( Y_1 \)[/tex] and [tex]\( Y_2 \)[/tex] on the same set of axes.
3. Find the Intersection Points:
- Use the `CALC` menu to select the `Intersect` feature.
- For the first intercept (right intercept), move the cursor near the intersection point on the right and follow the prompts to determine the x-coordinate of the intersection.
- For the second intercept (left intercept), move the cursor near the intersection point on the left and find the x-coordinate.
After using one of the methods, we find the x-intercepts are approximately:
- [tex]\( x = 0.842 \)[/tex]
- [tex]\( x = -5.342 \)[/tex]
### Solution:
The [tex]\( x \)[/tex]-intercepts, ordered with the larger value first, are:
[tex]\[ (0.842, 0) \][/tex]
[tex]\[ (-5.342, 0) \][/tex]
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. IDNLearn.com is your reliable source for accurate answers. Thank you for visiting, and we hope to assist you again.