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\begin{tabular}{|l|l|l|}
\hline
1.2 & & \\
\hline
& & \\
\hline
& & \\
\hline
1.2.1 & [tex]$3=$[/tex] & \\
\hline
1.2.2 & [tex]$\hat{4}=$[/tex] & \\
\hline
1.2.3 & [tex]$\hat{5}=$[/tex] & \\
\hline
1.2.4 & [tex]$\hat{3}+\hat{4}+\hat{5}=$[/tex] & \\
\hline
& & \\
\hline
\end{tabular}

Sagot :

GinnyAnsweridn
Let's analyze the given table and fill in the blanks step-by-step based on a logical progression and confirmed values:

[tex]\[ \begin{tabular}{|c|c|c|} \hline 1.2 & & \\ \hline & & \\ \hline & & \\ \hline 1.2 & 3 & \\ \hline 1.2 & 4 & \\ \hline 1.2 & 5 & \\ \hline 1.2 & & \\ \hline & & \\ \hline \end{tabular} \][/tex]

1. Top Cell (1.2, ?, ?)
- We see that the value 1.2 is confirmed at the start of each row apart from the second and third rows.

2. Second and Third Rows
- As there is no additional data for these cells, it is logical to conclude that these cells remain as they are.

3. Fourth to Sixth Rows
- The values in these rows follow a recognizable pattern:
- Fourth row: 1.2 and 3 at the second column.
- Fifth row: 1.2 and 4 at the second column.
- Sixth row: 1.2 and 5 at the second column.

4. Seventh Row (1.2, ?, ?)
- The cell values do not disrupt the existing patterns. Hence, we assume the validated values hold without further changes.

Combining all the information from the grid, our final filled table is:

[tex]\[ \begin{tabular}{|c|c|c|} \hline 1.2 & \text{None} & \text{None} \\ \hline \text{None} & \text{None} & \text{None} \\ \hline \text{None} & \text{None} & \text{None} \\ \hline 1.2 & 3 & \text{None} \\ \hline 1.2 & 4 & \text{None} \\ \hline 1.2 & 5 & \text{None} \\ \hline 1.2 & \text{None} & \text{None} \\ \hline \text{None} & \text{None} & \text{None} \\ \hline \end{tabular} \][/tex]
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