IDNLearn.com: Your one-stop destination for reliable answers to diverse questions. Our platform offers comprehensive and accurate responses to help you make informed decisions on any topic.

Using rational approximations, which statement is true?

A. [tex]\sqrt{12}\ \textless \ \pi[/tex]
B. [tex]\sqrt{16}\ \textgreater \ 4[/tex]
C. [tex]\sqrt{12}\ \textgreater \ \pi[/tex]
D. [tex]\sqrt{16}\ \textless \ 4[/tex]


Sagot :

To determine which statement is true, we need to approximate the values of [tex]\(\sqrt{12}\)[/tex], [tex]\(\pi\)[/tex], and [tex]\(\sqrt{16}\)[/tex], and then compare them.

Let's start with [tex]\(\sqrt{12}\)[/tex] and [tex]\(\sqrt{16}\)[/tex]:
- [tex]\(\sqrt{12} \approx 3.4641\)[/tex]
- [tex]\(\sqrt{16} = 4\)[/tex]

Next, recall the value of [tex]\(\pi\)[/tex]:
- [tex]\(\pi \approx 3.1416\)[/tex]

Now, let's evaluate each of the given inequalities:

1. [tex]\(\sqrt{12} < \pi\)[/tex]
- [tex]\(\sqrt{12} \approx 3.4641\)[/tex] is not less than [tex]\(\pi \approx 3.1416\)[/tex].
- This statement is False.

2. [tex]\(\sqrt{16} > 4\)[/tex]
- [tex]\(\sqrt{16} = 4\)[/tex] is not greater than 4.
- This statement is False.

3. [tex]\(\sqrt{12} > \pi\)[/tex]
- [tex]\(\sqrt{12} \approx 3.4641\)[/tex] is indeed greater than [tex]\(\pi \approx 3.1416\)[/tex].
- This statement is True.

4. [tex]\(\sqrt{16} < 4\)[/tex]
- [tex]\(\sqrt{16} = 4\)[/tex] is not less than 4.
- This statement is False.

After evaluating each of the statements, we find that the true statement is:
[tex]\[ \sqrt{12} > \pi \][/tex]