Get expert advice and community support for your questions on IDNLearn.com. Ask your questions and receive prompt, detailed answers from our experienced and knowledgeable community members.
Sagot :
Let's evaluate each system of equations one by one to see if it is equivalent to the original system:
Original System:
[tex]\[ \begin{array}{l} 4x - y = -11 \\ 2x + 3y = 5 \end{array} \][/tex]
### Equivalent System 1:
[tex]\[ \begin{array}{l} 4x + 3y = 5 \\ 2y = -6 \end{array} \][/tex]
1. The first equation in Equivalent System 1:
[tex]\[ 4x + 3y = 5 \][/tex]
is different from both equations in the original system, indicating this system is not equivalent.
### Equivalent System 2:
[tex]\[ \begin{array}{l} 7x - 3y = -11 \\ 9x = -6 \end{array} \][/tex]
1. The second equation:
[tex]\[ 9x = -6 \quad \Rightarrow \quad x = -\frac{2}{3} \][/tex]
Substitute [tex]\( x = -\frac{2}{3} \)[/tex] into the first equation:
[tex]\[ 7\left(-\frac{2}{3}\right) - 3y = -11 \quad \Rightarrow \quad -\frac{14}{3} - 3y = -11 \quad \Rightarrow \quad -3y = -11 + \frac{14}{3} \quad \Rightarrow \quad -3y = -\frac{19}{3} \quad \Rightarrow \quad y = \frac{19}{9} \][/tex]
2. Plugging these solutions into the original equations shows that they do not satisfy both, indicating this system is also not equivalent.
### Equivalent System 3:
[tex]\[ \begin{array}{l} -4x - 9y = -19 \\ -10y = -30 \end{array} \][/tex]
1. The second equation:
[tex]\[ -10y = -30 \quad \Rightarrow \quad y = 3 \][/tex]
Substitute [tex]\( y = 3 \)[/tex] into the first equation:
[tex]\[ -4x - 9(3) = -19 \quad \Rightarrow \quad -4x - 27 = -19 \quad \Rightarrow \quad -4x = 8 \quad \Rightarrow \quad x = -2 \][/tex]
2. Check:
[tex]\[ 4(-2) - 3 = -11 \quad \text{and} \quad 2(-2) + 3(3) = 5 \][/tex]
Both original equations are satisfied, indicating this system is equivalent.
### Equivalent System 4:
[tex]\[ \begin{array}{l} 12x - 3y = -33 \\ 14x = -28 \end{array} \][/tex]
1. The second equation:
[tex]\[ 14x = -28 \quad \Rightarrow \quad x = -2 \][/tex]
Substitute [tex]\( x = -2 \)[/tex] into the first equation:
[tex]\[ 12(-2) - 3y = -33 \quad \Rightarrow \quad -24 - 3y = -33 \quad \Rightarrow \quad -3y = -9 \quad \Rightarrow \quad y = 3 \][/tex]
2. Check:
[tex]\[ 4(-2) - 3 = -11 \quad \text{and} \quad 2(-2) + 3(3) = 5 \][/tex]
Both original equations are satisfied, indicating this system is equivalent.
Answer: Both System 3 and System 4 are equivalent to the original system.
Original System:
[tex]\[ \begin{array}{l} 4x - y = -11 \\ 2x + 3y = 5 \end{array} \][/tex]
### Equivalent System 1:
[tex]\[ \begin{array}{l} 4x + 3y = 5 \\ 2y = -6 \end{array} \][/tex]
1. The first equation in Equivalent System 1:
[tex]\[ 4x + 3y = 5 \][/tex]
is different from both equations in the original system, indicating this system is not equivalent.
### Equivalent System 2:
[tex]\[ \begin{array}{l} 7x - 3y = -11 \\ 9x = -6 \end{array} \][/tex]
1. The second equation:
[tex]\[ 9x = -6 \quad \Rightarrow \quad x = -\frac{2}{3} \][/tex]
Substitute [tex]\( x = -\frac{2}{3} \)[/tex] into the first equation:
[tex]\[ 7\left(-\frac{2}{3}\right) - 3y = -11 \quad \Rightarrow \quad -\frac{14}{3} - 3y = -11 \quad \Rightarrow \quad -3y = -11 + \frac{14}{3} \quad \Rightarrow \quad -3y = -\frac{19}{3} \quad \Rightarrow \quad y = \frac{19}{9} \][/tex]
2. Plugging these solutions into the original equations shows that they do not satisfy both, indicating this system is also not equivalent.
### Equivalent System 3:
[tex]\[ \begin{array}{l} -4x - 9y = -19 \\ -10y = -30 \end{array} \][/tex]
1. The second equation:
[tex]\[ -10y = -30 \quad \Rightarrow \quad y = 3 \][/tex]
Substitute [tex]\( y = 3 \)[/tex] into the first equation:
[tex]\[ -4x - 9(3) = -19 \quad \Rightarrow \quad -4x - 27 = -19 \quad \Rightarrow \quad -4x = 8 \quad \Rightarrow \quad x = -2 \][/tex]
2. Check:
[tex]\[ 4(-2) - 3 = -11 \quad \text{and} \quad 2(-2) + 3(3) = 5 \][/tex]
Both original equations are satisfied, indicating this system is equivalent.
### Equivalent System 4:
[tex]\[ \begin{array}{l} 12x - 3y = -33 \\ 14x = -28 \end{array} \][/tex]
1. The second equation:
[tex]\[ 14x = -28 \quad \Rightarrow \quad x = -2 \][/tex]
Substitute [tex]\( x = -2 \)[/tex] into the first equation:
[tex]\[ 12(-2) - 3y = -33 \quad \Rightarrow \quad -24 - 3y = -33 \quad \Rightarrow \quad -3y = -9 \quad \Rightarrow \quad y = 3 \][/tex]
2. Check:
[tex]\[ 4(-2) - 3 = -11 \quad \text{and} \quad 2(-2) + 3(3) = 5 \][/tex]
Both original equations are satisfied, indicating this system is equivalent.
Answer: Both System 3 and System 4 are equivalent to the original system.
Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.