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What is the solution to the following inequality?

[tex]\[ \frac{x}{-3} \leq 3 \][/tex]

A. [tex]\( x \leq -9 \)[/tex]
B. [tex]\( x \geq 1 \)[/tex]
C. [tex]\( x \geq -9 \)[/tex]
D. [tex]\( x \geq 6 \)[/tex]


Sagot :

To solve the inequality [tex]\(\frac{x}{-3} \leq 3\)[/tex], we need to isolate [tex]\(x\)[/tex]. Here is the step-by-step process:

1. Start with the given inequality:
[tex]\[ \frac{x}{-3} \leq 3 \][/tex]

2. To clear the fraction, we multiply both sides of the inequality by [tex]\(-3\)[/tex].

Note: When multiplying or dividing both sides of an inequality by a negative number, the direction of the inequality sign reverses.

Doing this, we get:
[tex]\[ x \geq 3 \times (-3) \][/tex]

3. Calculate the right-hand side:
[tex]\[ 3 \times (-3) = -9 \][/tex]

4. Therefore, the inequality becomes:
[tex]\[ x \geq -9 \][/tex]

Thus, the solution to the inequality [tex]\(\frac{x}{-3} \leq 3\)[/tex] is:
[tex]\[ x \geq -9 \][/tex]

So, the correct answer is:

C. [tex]\(x \geq -9\)[/tex]