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What is the value of [tex]$x$[/tex] in the proportion below?

[tex]\frac{19}{40}=\frac{x}{3.6}[/tex]

A. 7.2
B. 1.71
C. 3
D. 11


Sagot :

To solve for [tex]\( x \)[/tex] in the given proportion:
[tex]\[ \frac{19}{40} = \frac{x}{3.6} \][/tex]

we use the property of proportions which states that if [tex]\(\frac{a}{b} = \frac{c}{d}\)[/tex], then [tex]\( a \cdot d = b \cdot c \)[/tex].

Here, [tex]\( a = 19 \)[/tex], [tex]\( b = 40 \)[/tex], [tex]\( c = x \)[/tex], and [tex]\( d = 3.6 \)[/tex]. Therefore, we can write:

[tex]\[ 19 \cdot 3.6 = 40 \cdot x \][/tex]

Next, we solve for [tex]\( x \)[/tex]:

[tex]\[ x = \frac{19 \cdot 3.6}{40} \][/tex]

Calculating the numerator [tex]\( 19 \cdot 3.6 \)[/tex]:

[tex]\[ 19 \cdot 3.6 = 68.4 \][/tex]

Now, divide by the denominator 40:

[tex]\[ x = \frac{68.4}{40} = 1.71 \][/tex]

Therefore, the value of [tex]\( x \)[/tex] is [tex]\( 1.71 \)[/tex], and the correct answer is:

[tex]\[ \boxed{1.71} \][/tex]
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