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Points [tex]\(B\)[/tex] and [tex]\(C\)[/tex] lie on a circle with center [tex]\(O\)[/tex] and a radius of 15 units. If the length of [tex]\(\operatorname{arc} BC\)[/tex] is [tex]\(21 \pi\)[/tex] units, what is [tex]\(m \angle BOC\)[/tex] in radians?

A. [tex]\(\frac{7}{5} \pi\)[/tex]

B. [tex]\(0.7 \pi\)[/tex]

C. [tex]\(1.2 \pi\)[/tex]

D. [tex]\(\frac{3}{5} \pi\)[/tex]


Sagot :

Certainly! To determine the measure of angle [tex]\( \angle BOC \)[/tex] in radians, given that the radius of the circle is [tex]\(15\)[/tex] units and the length of the arc [tex]\( BC \)[/tex] is [tex]\(21\pi\)[/tex] units, we can follow these steps:

1. Recall the formula for the arc length:
The length of an arc [tex]\( s \)[/tex] of a circle can be calculated using the formula [tex]\( s = r\theta \)[/tex], where [tex]\( r \)[/tex] is the radius of the circle and [tex]\( \theta \)[/tex] is the central angle in radians.

2. Identify the given values:
- Radius [tex]\( r = 15 \)[/tex] units
- Arc length [tex]\( s = 21\pi \)[/tex] units

3. Set up the equation:
Given the formula [tex]\( s = r\theta \)[/tex], substitute the values:
[tex]\[ 21\pi = 15\theta \][/tex]

4. Solve for [tex]\( \theta \)[/tex]:
Divide both sides of the equation by [tex]\( 15 \)[/tex]:
[tex]\[ \theta = \frac{21\pi}{15} \][/tex]

5. Simplify the fraction:
Simplify [tex]\( \frac{21\pi}{15} \)[/tex]:
[tex]\[ \theta = \frac{21}{15}\pi = \frac{7}{5}\pi \][/tex]

Therefore, the measure of [tex]\( \angle BOC \)[/tex] in radians is [tex]\(\frac{7}{5}\pi\)[/tex].

So, the correct answer is:
A. [tex]\(\frac{7}{5}\pi\)[/tex]