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If [tex]f(x)=\sqrt{x}+12[/tex] and [tex]g(x)=2 \sqrt{x}[/tex], what is the value of [tex](f-g)(144)[/tex]?

A. [tex]-84[/tex]
B. [tex]-60[/tex]
C. 0
D. 48


Sagot :

To solve for [tex]\((f-g)(144)\)[/tex], we first need to determine the expressions for [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex]:

- [tex]\(f(x) = \sqrt{x} + 12\)[/tex]
- [tex]\(g(x) = 2 \sqrt{x}\)[/tex]

Next, we need to evaluate these functions at [tex]\(x = 144\)[/tex].

First, evaluate [tex]\(f(144)\)[/tex]:

[tex]\[ f(144) = \sqrt{144} + 12 \][/tex]

We know that [tex]\(\sqrt{144} = 12\)[/tex], so:

[tex]\[ f(144) = 12 + 12 = 24 \][/tex]

Now, evaluate [tex]\(g(144)\)[/tex]:

[tex]\[ g(144) = 2 \sqrt{144} \][/tex]

Again, knowing that [tex]\(\sqrt{144} = 12\)[/tex], we get:

[tex]\[ g(144) = 2 \times 12 = 24 \][/tex]

Now we need to find [tex]\((f - g)(144)\)[/tex]:

[tex]\[ (f - g)(144) = f(144) - g(144) \][/tex]

Substitute the values we found:

[tex]\[ (f - g)(144) = 24 - 24 = 0 \][/tex]

Therefore, the value of [tex]\((f - g)(144)\)[/tex] is [tex]\( \boxed{0} \)[/tex].