Get the most out of your questions with IDNLearn.com's extensive resources. Our platform is designed to provide accurate and comprehensive answers to any questions you may have.
Sagot :
Sure, let's work through the problem step by step.
We are given two functions, [tex]\( f(x) \)[/tex] and [tex]\( g(x) \)[/tex]:
[tex]\[ f(x) = 3 - 2x \][/tex]
[tex]\[ g(x) = \frac{1}{x + 5} \][/tex]
We need to find the value of [tex]\( \left(\frac{f}{g}\right)(8) \)[/tex]. This means we need to calculate [tex]\( \frac{f(8)}{g(8)} \)[/tex].
First, let's find [tex]\( f(8) \)[/tex]:
[tex]\[ f(8) = 3 - 2 \cdot 8 \][/tex]
[tex]\[ f(8) = 3 - 16 \][/tex]
[tex]\[ f(8) = -13 \][/tex]
Next, let's find [tex]\( g(8) \)[/tex]:
[tex]\[ g(8) = \frac{1}{8 + 5} \][/tex]
[tex]\[ g(8) = \frac{1}{13} \][/tex]
Now we need to find [tex]\( \frac{f(8)}{g(8)} \)[/tex]:
[tex]\[ \frac{f(8)}{g(8)} = \frac{-13}{\frac{1}{13}} \][/tex]
To divide by a fraction, we multiply by its reciprocal:
[tex]\[ \frac{-13}{\frac{1}{13}} = -13 \times 13 \][/tex]
[tex]\[ -13 \times 13 = -169 \][/tex]
Therefore, the value of [tex]\( \left(\frac{f}{g}\right)(8) \)[/tex] is:
[tex]\[ \boxed{-169} \][/tex]
We are given two functions, [tex]\( f(x) \)[/tex] and [tex]\( g(x) \)[/tex]:
[tex]\[ f(x) = 3 - 2x \][/tex]
[tex]\[ g(x) = \frac{1}{x + 5} \][/tex]
We need to find the value of [tex]\( \left(\frac{f}{g}\right)(8) \)[/tex]. This means we need to calculate [tex]\( \frac{f(8)}{g(8)} \)[/tex].
First, let's find [tex]\( f(8) \)[/tex]:
[tex]\[ f(8) = 3 - 2 \cdot 8 \][/tex]
[tex]\[ f(8) = 3 - 16 \][/tex]
[tex]\[ f(8) = -13 \][/tex]
Next, let's find [tex]\( g(8) \)[/tex]:
[tex]\[ g(8) = \frac{1}{8 + 5} \][/tex]
[tex]\[ g(8) = \frac{1}{13} \][/tex]
Now we need to find [tex]\( \frac{f(8)}{g(8)} \)[/tex]:
[tex]\[ \frac{f(8)}{g(8)} = \frac{-13}{\frac{1}{13}} \][/tex]
To divide by a fraction, we multiply by its reciprocal:
[tex]\[ \frac{-13}{\frac{1}{13}} = -13 \times 13 \][/tex]
[tex]\[ -13 \times 13 = -169 \][/tex]
Therefore, the value of [tex]\( \left(\frac{f}{g}\right)(8) \)[/tex] is:
[tex]\[ \boxed{-169} \][/tex]
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. IDNLearn.com is committed to your satisfaction. Thank you for visiting, and see you next time for more helpful answers.