IDNLearn.com is your go-to platform for finding reliable answers quickly. Our platform provides prompt, accurate answers from experts ready to assist you with any question you may have.

The volume of an oblique pyramid with a square base is [tex]V[/tex] units[tex]\(^3\)[/tex] and the height is [tex]h[/tex] units. Which expression represents the area of the base of the pyramid?

A. [tex]\frac{3V}{h}[/tex] units[tex]\(^2\)[/tex]

B. [tex]3V - h[/tex] units[tex]\(^2\)[/tex]

C. [tex]V - 3h[/tex] units[tex]\(^2\)[/tex]


Sagot :

To find the area of the base of an oblique pyramid with a square base and given volume [tex]\( V \)[/tex] and height [tex]\( h \)[/tex], let's use the relationship between the volume, base area, and height of a pyramid.

The volume [tex]\( V \)[/tex] of a pyramid is given by the formula:
[tex]\[ V = \frac{1}{3} \times \text{BaseArea} \times h \][/tex]

Here, we need to solve for the BaseArea. We start by isolating BaseArea in the equation:
[tex]\[ V = \frac{1}{3} \times \text{BaseArea} \times h \][/tex]

First, multiply both sides by 3 to clear the fraction:
[tex]\[ 3V = \text{BaseArea} \times h \][/tex]

Next, divide both sides by [tex]\( h \)[/tex] to solve for \text{BaseArea}:
[tex]\[ \text{BaseArea} = \frac{3V}{h} \][/tex]

So, the expression that represents the area of the base of the pyramid is:
[tex]\[ \frac{3V}{h} \text{ units }^2 \][/tex]

Among the given options, the correct expression is:
[tex]\[ \boxed{\frac{3 V}{h} \text{ units }^{2}} \][/tex]