Certainly! Let's go through the hints provided and deduce the IUPAC names of substances 'A' and 'F' step by step.
### Hint Analysis
Hint (i):
- Substance 'C' is used as a preservative.
Hint (ii):
- 'C' has two carbon atoms.
- 'C' is obtained from the reaction of 'A' in the presence of alkaline potassium permanganate followed by acidification.
Hint (iii):
- Misuse of 'A' in industries is prevented by adding Methanol, Benzene, and Pyridine to 'A'.
Hint (iv):
- This hint is missing, so we'll move on to the next.
Hint (v):
- 'F' is formed when 'A' is heated in the presence of concentrated sulfuric acid.
### Step-by-Step Deduction
1. Identifying Substance 'A':
- Based on Hint (iii), substance ‘A’ is something whose misuse is prevented by adding methanol, benzene, and pyridine. These chemicals are commonly added to ethanol to make it denatured (toxic and undrinkable) for industrial use. Hence, substance 'A' is ethanol.
2. Identifying Substance 'C':
- Hint (ii) reveals that ‘C’ has two carbon atoms and is obtained by oxidizing 'A' (ethanol). When ethanol undergoes oxidation with alkaline potassium permanganate followed by acidification, it forms acetic acid (ethanoic acid), which has two carbon atoms. Additionally, acetic acid is a well-known preservative. Hence, substance 'C' is acetic acid.
3. Identifying Substance 'F':
- According to Hint (v), when 'A' (ethanol) is heated in the presence of concentrated sulfuric acid, it undergoes dehydration to produce ethene (an alkene).
### Conclusion
Based on the above deductions,
- The IUPAC name of 'A' is ethanol.
- The IUPAC name of 'F' is ethene.
Therefore, the answers are:
- A: Ethanol
- F: Ethene
