Join IDNLearn.com and become part of a knowledge-sharing community that thrives on curiosity. Ask anything and receive prompt, well-informed answers from our community of experienced experts.
Sagot :
Sure! I'll walk through each equation step-by-step to show how to solve them.
### Equation 7: [tex]\(\frac{x-4}{3} - 5 = 0\)[/tex]
1. Start by isolating the term with [tex]\(x\)[/tex]:
[tex]\[ \frac{x-4}{3} = 5 \][/tex]
2. Multiply both sides by 3 to clear the fraction:
[tex]\[ x - 4 = 15 \][/tex]
3. Add 4 to both sides to solve for [tex]\(x\)[/tex]:
[tex]\[ x = 19 \][/tex]
So, [tex]\( x = 19 \)[/tex].
### Equation 8: [tex]\( x - \frac{x+2}{12} = \frac{5x}{2} \)[/tex]
1. Start by clearing the fraction by multiplying every term by 12:
[tex]\[ 12x - (x + 2) = 6 \times 5x \][/tex]
2. Simplify the equation:
[tex]\[ 12x - x - 2 = 30x \][/tex]
[tex]\[ 11x - 2 = 30x \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ 11x - 30x = 2 \][/tex]
[tex]\[ -19x = 2 \][/tex]
4. Divide by -19 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = -\frac{2}{19} \][/tex]
So, [tex]\( x = -\frac{2}{19} \)[/tex].
### Equation 9: [tex]\( x - \frac{5x-1}{3} = 4x - \frac{3}{5} \)[/tex]
1. Clear the fractions by multiplying every term by 15 (LCM of 3 and 5):
[tex]\[ 15x - 5(5x - 1) = 60x - 3 \][/tex]
2. Expand and simplify:
[tex]\[ 15x - 25x + 5 = 60x - 3 \][/tex]
[tex]\[ -10x + 5 = 60x - 3 \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ -10x - 60x = -3 - 5 \][/tex]
[tex]\[ -70x = -8 \][/tex]
4. Divide by -70 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{-8}{-70} = \frac{8}{70} = \frac{4}{35} \approx 0.114 \][/tex]
So, [tex]\( x \approx 0.200 \)[/tex]. (Correction: It's exact [tex]\(0.200\)[/tex])
### Equation 10: [tex]\( 10x - \frac{8x - 3}{4} = 2(x - 3) \)[/tex]
1. Clear the fraction by multiplying every term by 4:
[tex]\[ 40x - (8x - 3) = 8(x - 3) \][/tex]
2. Distribute and simplify:
[tex]\[ 40x - 8x + 3 = 8x - 24 \][/tex]
[tex]\[ 32x + 3 = 8x - 24 \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ 32x - 8x = -24 - 3 \][/tex]
[tex]\[ 24x = -27 \][/tex]
4. Divide by 24 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = -\frac{27}{24} = -\frac{9}{8} \][/tex]
So, [tex]\( x = -\frac{9}{8} \)[/tex].
### Equation 11: [tex]\(\frac{x-2}{3} - \frac{x-3}{4} = \frac{x-4}{5} \)[/tex]
1. Clear the fractions by multiplying every term by 60 (LCM of 3, 4, and 5):
[tex]\[ 20(x - 2) - 15(x - 3) = 12(x - 4) \][/tex]
2. Distribute and simplify:
[tex]\[ 20x - 40 - 15x + 45 = 12x - 48 \][/tex]
[tex]\[ 5x + 5 = 12x - 48 \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ 5x - 12x = -48 - 5 \][/tex]
[tex]\[ -7x = -53 \][/tex]
4. Divide by -7 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{53}{7} \][/tex]
So, [tex]\( x = \frac{53}{7} \)[/tex].
### Equation 12: [tex]\(\frac{x-1}{2} - \frac{x-2}{3} - \frac{x-3}{4} = -\frac{x-5}{5} \)[/tex]
1. Clear the fractions by multiplying every term by 60 (LCM of 2, 3, 4, and 5):
[tex]\[ 30(x - 1) - 20(x - 2) - 15(x - 3) = -12(x - 5) \][/tex]
2. Distribute and simplify:
[tex]\[ 30x - 30 - 20x + 40 - 15x + 45 = -12x + 60 \][/tex]
[tex]\[ (30x - 20x - 15x) = (-12x + 60 + 30 - 40 - 45) \][/tex]
[tex]\[ -5x - 30 + 40 + 45 = -12x + 60 \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ -5x + 12x = -30 + 40 + 45 - 60 \][/tex]
[tex]\[ 7x = 5 \][/tex]
4. Divide by 7 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{5}{7} \][/tex]
So, [tex]\( x = \frac{5}{7} \)[/tex].
### Equation 13: [tex]\( x - (5x - 1) - \frac{7 - 5x}{10} = 1 \)[/tex]
1. Clear the fraction by multiplying every term by 10:
[tex]\[ 10x - 10(5x - 1) - (7 - 5x) = 10 \][/tex]
2. Distribute and simplify:
[tex]\[ 10x - 50x + 10 - 7 + 5x = 10 \][/tex]
[tex]\[ (10x - 50x + 5x) + 10 - 7 = 10 \][/tex]
[tex]\[ -35x + 10 -7 = 10 \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ -35x + 3 = 10 \][/tex]
[tex]\[ -35x = 7 \][/tex]
4. Divide by -35 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = -\frac{7}{35} = -\frac{1}{5} \][/tex]
So, [tex]\( x = -\frac{1}{5} \)[/tex].
### Equation 14: [tex]\( 2x - \frac{5x - 6}{4} + \frac{1}{3}(x - 5) = -5x \)[/tex]
1. Clear the fraction by multiplying every term by 12 (LCM of 4 and 3):
[tex]\[ 24x - 3(5x - 6) + 4(x - 5) = -60x \][/tex]
2. Distribute and simplify:
[tex]\[ 24x - 15x + 18 + 4x - 20 = -60x \][/tex]
[tex]\[ (24x - 15x + 4x) + (18 - 20) = -60x \][/tex]
[tex]\[ 13x - 2 = -60x \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ 13x + 60x = 2 \][/tex]
[tex]\[ 73x = 73 \][/tex]
4. Divide by 73 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{2}{73} \][/tex]
So, [tex]\( x = \approx 0.0273972602739726 \)[/tex] (Exact: not fraction)
### Equation 15: [tex]\( 4 - \frac{10x + 1}{6} = 4x - \frac{16x + 3}{4} \)[/tex]
1. Clear the fraction by multiplying every term by 12 (LCM of 6 and 4):
[tex]\[ 48 - 2(10x + 1) = 12 * 4x - 3(16x + 3) \][/tex]
2. Distribute and simplify:
[tex]\[ 48 - 20x - 2 = 48x - 48x - 9 \][/tex]
[tex]\[ 46 - 20x = 48x - 9 \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ 46 = 48x - 9 + 20x \][/tex]
[tex]\[ 75= 48x + 20 x = 53 \][/tex]
\]
4. Divide by 4 to solve for [tex]\(x\)[/tex]:
\[
x = \frac{11}{4} = develop exact . calculation
]
So, \( x = 11/4).
### Equation 7: [tex]\(\frac{x-4}{3} - 5 = 0\)[/tex]
1. Start by isolating the term with [tex]\(x\)[/tex]:
[tex]\[ \frac{x-4}{3} = 5 \][/tex]
2. Multiply both sides by 3 to clear the fraction:
[tex]\[ x - 4 = 15 \][/tex]
3. Add 4 to both sides to solve for [tex]\(x\)[/tex]:
[tex]\[ x = 19 \][/tex]
So, [tex]\( x = 19 \)[/tex].
### Equation 8: [tex]\( x - \frac{x+2}{12} = \frac{5x}{2} \)[/tex]
1. Start by clearing the fraction by multiplying every term by 12:
[tex]\[ 12x - (x + 2) = 6 \times 5x \][/tex]
2. Simplify the equation:
[tex]\[ 12x - x - 2 = 30x \][/tex]
[tex]\[ 11x - 2 = 30x \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ 11x - 30x = 2 \][/tex]
[tex]\[ -19x = 2 \][/tex]
4. Divide by -19 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = -\frac{2}{19} \][/tex]
So, [tex]\( x = -\frac{2}{19} \)[/tex].
### Equation 9: [tex]\( x - \frac{5x-1}{3} = 4x - \frac{3}{5} \)[/tex]
1. Clear the fractions by multiplying every term by 15 (LCM of 3 and 5):
[tex]\[ 15x - 5(5x - 1) = 60x - 3 \][/tex]
2. Expand and simplify:
[tex]\[ 15x - 25x + 5 = 60x - 3 \][/tex]
[tex]\[ -10x + 5 = 60x - 3 \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ -10x - 60x = -3 - 5 \][/tex]
[tex]\[ -70x = -8 \][/tex]
4. Divide by -70 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{-8}{-70} = \frac{8}{70} = \frac{4}{35} \approx 0.114 \][/tex]
So, [tex]\( x \approx 0.200 \)[/tex]. (Correction: It's exact [tex]\(0.200\)[/tex])
### Equation 10: [tex]\( 10x - \frac{8x - 3}{4} = 2(x - 3) \)[/tex]
1. Clear the fraction by multiplying every term by 4:
[tex]\[ 40x - (8x - 3) = 8(x - 3) \][/tex]
2. Distribute and simplify:
[tex]\[ 40x - 8x + 3 = 8x - 24 \][/tex]
[tex]\[ 32x + 3 = 8x - 24 \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ 32x - 8x = -24 - 3 \][/tex]
[tex]\[ 24x = -27 \][/tex]
4. Divide by 24 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = -\frac{27}{24} = -\frac{9}{8} \][/tex]
So, [tex]\( x = -\frac{9}{8} \)[/tex].
### Equation 11: [tex]\(\frac{x-2}{3} - \frac{x-3}{4} = \frac{x-4}{5} \)[/tex]
1. Clear the fractions by multiplying every term by 60 (LCM of 3, 4, and 5):
[tex]\[ 20(x - 2) - 15(x - 3) = 12(x - 4) \][/tex]
2. Distribute and simplify:
[tex]\[ 20x - 40 - 15x + 45 = 12x - 48 \][/tex]
[tex]\[ 5x + 5 = 12x - 48 \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ 5x - 12x = -48 - 5 \][/tex]
[tex]\[ -7x = -53 \][/tex]
4. Divide by -7 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{53}{7} \][/tex]
So, [tex]\( x = \frac{53}{7} \)[/tex].
### Equation 12: [tex]\(\frac{x-1}{2} - \frac{x-2}{3} - \frac{x-3}{4} = -\frac{x-5}{5} \)[/tex]
1. Clear the fractions by multiplying every term by 60 (LCM of 2, 3, 4, and 5):
[tex]\[ 30(x - 1) - 20(x - 2) - 15(x - 3) = -12(x - 5) \][/tex]
2. Distribute and simplify:
[tex]\[ 30x - 30 - 20x + 40 - 15x + 45 = -12x + 60 \][/tex]
[tex]\[ (30x - 20x - 15x) = (-12x + 60 + 30 - 40 - 45) \][/tex]
[tex]\[ -5x - 30 + 40 + 45 = -12x + 60 \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ -5x + 12x = -30 + 40 + 45 - 60 \][/tex]
[tex]\[ 7x = 5 \][/tex]
4. Divide by 7 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{5}{7} \][/tex]
So, [tex]\( x = \frac{5}{7} \)[/tex].
### Equation 13: [tex]\( x - (5x - 1) - \frac{7 - 5x}{10} = 1 \)[/tex]
1. Clear the fraction by multiplying every term by 10:
[tex]\[ 10x - 10(5x - 1) - (7 - 5x) = 10 \][/tex]
2. Distribute and simplify:
[tex]\[ 10x - 50x + 10 - 7 + 5x = 10 \][/tex]
[tex]\[ (10x - 50x + 5x) + 10 - 7 = 10 \][/tex]
[tex]\[ -35x + 10 -7 = 10 \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ -35x + 3 = 10 \][/tex]
[tex]\[ -35x = 7 \][/tex]
4. Divide by -35 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = -\frac{7}{35} = -\frac{1}{5} \][/tex]
So, [tex]\( x = -\frac{1}{5} \)[/tex].
### Equation 14: [tex]\( 2x - \frac{5x - 6}{4} + \frac{1}{3}(x - 5) = -5x \)[/tex]
1. Clear the fraction by multiplying every term by 12 (LCM of 4 and 3):
[tex]\[ 24x - 3(5x - 6) + 4(x - 5) = -60x \][/tex]
2. Distribute and simplify:
[tex]\[ 24x - 15x + 18 + 4x - 20 = -60x \][/tex]
[tex]\[ (24x - 15x + 4x) + (18 - 20) = -60x \][/tex]
[tex]\[ 13x - 2 = -60x \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ 13x + 60x = 2 \][/tex]
[tex]\[ 73x = 73 \][/tex]
4. Divide by 73 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{2}{73} \][/tex]
So, [tex]\( x = \approx 0.0273972602739726 \)[/tex] (Exact: not fraction)
### Equation 15: [tex]\( 4 - \frac{10x + 1}{6} = 4x - \frac{16x + 3}{4} \)[/tex]
1. Clear the fraction by multiplying every term by 12 (LCM of 6 and 4):
[tex]\[ 48 - 2(10x + 1) = 12 * 4x - 3(16x + 3) \][/tex]
2. Distribute and simplify:
[tex]\[ 48 - 20x - 2 = 48x - 48x - 9 \][/tex]
[tex]\[ 46 - 20x = 48x - 9 \][/tex]
3. Get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ 46 = 48x - 9 + 20x \][/tex]
[tex]\[ 75= 48x + 20 x = 53 \][/tex]
\]
4. Divide by 4 to solve for [tex]\(x\)[/tex]:
\[
x = \frac{11}{4} = develop exact . calculation
]
So, \( x = 11/4).
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.