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Sagot :
To determine how many Earths can fit inside Jupiter, we'll divide the volume of Jupiter by the volume of Earth.
1. The volume of Jupiter is given as [tex]\(1.43 \times 10^{15}\)[/tex] cubic kilometers.
2. The volume of Earth is given as [tex]\(1.09 \times 10^{12}\)[/tex] cubic kilometers.
We need to perform the following division:
[tex]\[ \frac{1.43 \times 10^{15}}{1.09 \times 10^{12}} \][/tex]
We can rewrite this division by separating the coefficients from the powers of ten:
[tex]\[ \frac{1.43}{1.09} \times \frac{10^{15}}{10^{12}} \][/tex]
First, divide the coefficients:
[tex]\[ \frac{1.43}{1.09} \approx 1.311926605504587 \][/tex]
Next, divide the powers of ten:
[tex]\[ \frac{10^{15}}{10^{12}} = 10^{15-12} = 10^3 \][/tex]
Now, multiply the results of the coefficients and the powers of ten:
[tex]\[ 1.311926605504587 \times 10^3 \approx 1311.926605504587 \][/tex]
Therefore, the number of Earths that can fit inside Jupiter is approximately [tex]\(1311.926605504587\)[/tex].
To express this result in scientific notation, we round this to a significant figure, giving us:
[tex]\[ 1.311926605504587 \times 10^3 \approx 1.3 \times 10^3 \][/tex]
So, the correct answer is:
[tex]\[ 1.3 \times 10^3 \][/tex]
1. The volume of Jupiter is given as [tex]\(1.43 \times 10^{15}\)[/tex] cubic kilometers.
2. The volume of Earth is given as [tex]\(1.09 \times 10^{12}\)[/tex] cubic kilometers.
We need to perform the following division:
[tex]\[ \frac{1.43 \times 10^{15}}{1.09 \times 10^{12}} \][/tex]
We can rewrite this division by separating the coefficients from the powers of ten:
[tex]\[ \frac{1.43}{1.09} \times \frac{10^{15}}{10^{12}} \][/tex]
First, divide the coefficients:
[tex]\[ \frac{1.43}{1.09} \approx 1.311926605504587 \][/tex]
Next, divide the powers of ten:
[tex]\[ \frac{10^{15}}{10^{12}} = 10^{15-12} = 10^3 \][/tex]
Now, multiply the results of the coefficients and the powers of ten:
[tex]\[ 1.311926605504587 \times 10^3 \approx 1311.926605504587 \][/tex]
Therefore, the number of Earths that can fit inside Jupiter is approximately [tex]\(1311.926605504587\)[/tex].
To express this result in scientific notation, we round this to a significant figure, giving us:
[tex]\[ 1.311926605504587 \times 10^3 \approx 1.3 \times 10^3 \][/tex]
So, the correct answer is:
[tex]\[ 1.3 \times 10^3 \][/tex]
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