Answered

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A submarine has a crush depth (the depth at which the submarine's hull will collapse under water pressure) of 1000 ft
(1ft = 30.48cm). If the density of salt water is 1025kg m⁻³, calculate the maximum pressure which the hull can withstand. You may assume that the internal pressure of the air in the submarine cancels out any contribution from atmospheric pressure. Use the following constants: g = 9.81 ms⁻².

Sagot :

Macaroni31idn

Answer:

The maximum pressure that the submarine can withstand is 3,064,840.2 Pa.

Explanation:

To find the maximum pressure the hull of the submarine can withstand, calculate the fluid pressure at the submarine's crush depth.

The formula for fluid pressure is P = ρgh, where -

- P is pressure in Pa

- ρ is density in kg/m³

- g is acceleration due to gravity in m/s²

- h is height in meters

Before we can plug our givens in, we must make sure all values are in the proper units. Let's convert the crush depth from feet to meters.

There are 0.3048 meters in a foot. Multiply this number by the amount of feet to find the crush depth in meters.

0.3048 m/ft * 1000 ft = 304.8 m

Now we can plug our givens into the equation to calculate fluid pressure.

P = 1025 kg/m³ * 9.81 m/s² * 304.8 m = 3,064,840.2 Pa

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