IDNLearn.com makes it easy to find the right answers to your questions. Join our interactive community and access reliable, detailed answers from experienced professionals across a variety of topics.
Sagot :
Certainly! Let's go through each of the given expressions and simplify them step-by-step:
### Expression 1:
[tex]\[ \frac{2^3 \cdot 2^{-2}}{2^5} \][/tex]
1. Simplify the numerator:
- Using the property of exponents [tex]\(a^m \cdot a^n = a^{m+n}\)[/tex]:
[tex]\[ 2^3 \cdot 2^{-2} = 2^{3 + (-2)} = 2^{1} = 2 \][/tex]
2. Combine the simplified numerator with the denominator:
- Now, the expression is:
[tex]\[ \frac{2^1}{2^5} = 2^{1-5} = 2^{-4} \][/tex]
3. Simplify the exponent:
- A negative exponent indicates a reciprocal:
[tex]\[ 2^{-4} = \frac{1}{2^4} = \frac{1}{16} \][/tex]
So, the simplified form of the first expression is:
[tex]\[ \frac{2^3 \cdot 2^{-2}}{2^5} = \frac{1}{16} \][/tex]
### Expression 2:
[tex]\[ \left(a^3\right)^4 \cdot b^2 \cdot b^{-3} \][/tex]
1. Simplify the part [tex]\(\left(a^3\right)^4\)[/tex]:
- Using the property of exponents [tex]\((a^m)^n = a^{m \cdot n}\)[/tex]:
[tex]\[ \left(a^3\right)^4 = a^{3 \cdot 4} = a^{12} \][/tex]
2. Simplify the part [tex]\( b^2 \cdot b^{-3} \)[/tex]:
- Using the property of exponents [tex]\(a^m \cdot a^n = a^{m+n}\)[/tex]:
[tex]\[ b^2 \cdot b^{-3} = b^{2 + (-3)} = b^{-1} \][/tex]
3. Express [tex]\( b^{-1} \)[/tex] as a fraction:
- A negative exponent indicates a reciprocal:
[tex]\[ b^{-1} = \frac{1}{b} \][/tex]
4. Combine everything:
[tex]\[ a^{12} \cdot b^{-1} = \frac{a^{12}}{b} \][/tex]
So, the simplified form of the second expression is:
[tex]\[ \left(a^3\right)^4 \cdot b^2 \cdot b^{-3} = \frac{a^{12}}{b} \][/tex]
### Expression 3:
[tex]\[ \frac{P^2 \cdot (Q^2)^3}{P^1} \][/tex]
1. Simplify the part [tex]\((Q^2)^3\)[/tex]:
- Using the property of exponents [tex]\((a^m)^n = a^{m \cdot n}\)[/tex]:
[tex]\[ (Q^2)^3 = Q^{2 \cdot 3} = Q^6 \][/tex]
2. Combine the simplified parts [tex]\(P^2\)[/tex] and [tex]\(Q^6\)[/tex]:
- Now, the expression is:
[tex]\[ \frac{P^2 \cdot Q^6}{P} \][/tex]
3. Simplify by combining [tex]\(P^2\)[/tex] and [tex]\(P^1\)[/tex]:
- Using the property of exponents [tex]\(\frac{a^m}{a^n} = a^{m-n}\)[/tex]:
[tex]\[ \frac{P^2}{P^1} = P^{2-1} = P \][/tex]
4. Combine everything:
[tex]\[ P \cdot Q^6 \][/tex]
So, the simplified form of the third expression is:
[tex]\[ \frac{P^2 \cdot (Q^2)^3}{P^1} = P \cdot Q^6 \][/tex]
### Summary:
1. [tex]\(\frac{2^3 \cdot 2^{-2}}{2^5} = \frac{1}{16}\)[/tex]
2. [tex]\(\left(a^3\right)^4 \cdot b^2 \cdot b^{-3} = \frac{a^{12}}{b}\)[/tex]
3. [tex]\(\frac{P^2 \cdot (Q^2)^3}{P^1} = P \cdot Q^6\)[/tex]
### Expression 1:
[tex]\[ \frac{2^3 \cdot 2^{-2}}{2^5} \][/tex]
1. Simplify the numerator:
- Using the property of exponents [tex]\(a^m \cdot a^n = a^{m+n}\)[/tex]:
[tex]\[ 2^3 \cdot 2^{-2} = 2^{3 + (-2)} = 2^{1} = 2 \][/tex]
2. Combine the simplified numerator with the denominator:
- Now, the expression is:
[tex]\[ \frac{2^1}{2^5} = 2^{1-5} = 2^{-4} \][/tex]
3. Simplify the exponent:
- A negative exponent indicates a reciprocal:
[tex]\[ 2^{-4} = \frac{1}{2^4} = \frac{1}{16} \][/tex]
So, the simplified form of the first expression is:
[tex]\[ \frac{2^3 \cdot 2^{-2}}{2^5} = \frac{1}{16} \][/tex]
### Expression 2:
[tex]\[ \left(a^3\right)^4 \cdot b^2 \cdot b^{-3} \][/tex]
1. Simplify the part [tex]\(\left(a^3\right)^4\)[/tex]:
- Using the property of exponents [tex]\((a^m)^n = a^{m \cdot n}\)[/tex]:
[tex]\[ \left(a^3\right)^4 = a^{3 \cdot 4} = a^{12} \][/tex]
2. Simplify the part [tex]\( b^2 \cdot b^{-3} \)[/tex]:
- Using the property of exponents [tex]\(a^m \cdot a^n = a^{m+n}\)[/tex]:
[tex]\[ b^2 \cdot b^{-3} = b^{2 + (-3)} = b^{-1} \][/tex]
3. Express [tex]\( b^{-1} \)[/tex] as a fraction:
- A negative exponent indicates a reciprocal:
[tex]\[ b^{-1} = \frac{1}{b} \][/tex]
4. Combine everything:
[tex]\[ a^{12} \cdot b^{-1} = \frac{a^{12}}{b} \][/tex]
So, the simplified form of the second expression is:
[tex]\[ \left(a^3\right)^4 \cdot b^2 \cdot b^{-3} = \frac{a^{12}}{b} \][/tex]
### Expression 3:
[tex]\[ \frac{P^2 \cdot (Q^2)^3}{P^1} \][/tex]
1. Simplify the part [tex]\((Q^2)^3\)[/tex]:
- Using the property of exponents [tex]\((a^m)^n = a^{m \cdot n}\)[/tex]:
[tex]\[ (Q^2)^3 = Q^{2 \cdot 3} = Q^6 \][/tex]
2. Combine the simplified parts [tex]\(P^2\)[/tex] and [tex]\(Q^6\)[/tex]:
- Now, the expression is:
[tex]\[ \frac{P^2 \cdot Q^6}{P} \][/tex]
3. Simplify by combining [tex]\(P^2\)[/tex] and [tex]\(P^1\)[/tex]:
- Using the property of exponents [tex]\(\frac{a^m}{a^n} = a^{m-n}\)[/tex]:
[tex]\[ \frac{P^2}{P^1} = P^{2-1} = P \][/tex]
4. Combine everything:
[tex]\[ P \cdot Q^6 \][/tex]
So, the simplified form of the third expression is:
[tex]\[ \frac{P^2 \cdot (Q^2)^3}{P^1} = P \cdot Q^6 \][/tex]
### Summary:
1. [tex]\(\frac{2^3 \cdot 2^{-2}}{2^5} = \frac{1}{16}\)[/tex]
2. [tex]\(\left(a^3\right)^4 \cdot b^2 \cdot b^{-3} = \frac{a^{12}}{b}\)[/tex]
3. [tex]\(\frac{P^2 \cdot (Q^2)^3}{P^1} = P \cdot Q^6\)[/tex]
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.