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Sagot :
To find the [tex]\( y \)[/tex]-intercept of the function [tex]\( f(x) = -\frac{2}{9} x + \frac{1}{3} \)[/tex], we need to determine the value of the function when [tex]\( x = 0 \)[/tex].
The [tex]\( y \)[/tex]-intercept of a function [tex]\( f(x) \)[/tex] is the point where the function crosses the [tex]\( y \)[/tex]-axis. This occurs when [tex]\( x = 0 \)[/tex], so we evaluate the function at this point:
[tex]\[ f(0) = -\frac{2}{9}(0) + \frac{1}{3} \][/tex]
Since any number multiplied by zero is zero, this simplifies to:
[tex]\[ f(0) = 0 + \frac{1}{3} = \frac{1}{3} \][/tex]
Therefore, the [tex]\( y \)[/tex]-intercept of the function [tex]\( f(x) = -\frac{2}{9} x + \frac{1}{3} \)[/tex] is [tex]\( \frac{1}{3} \)[/tex].
So, the correct answer is:
[tex]\(\boxed{\frac{1}{3}}\)[/tex]
The [tex]\( y \)[/tex]-intercept of a function [tex]\( f(x) \)[/tex] is the point where the function crosses the [tex]\( y \)[/tex]-axis. This occurs when [tex]\( x = 0 \)[/tex], so we evaluate the function at this point:
[tex]\[ f(0) = -\frac{2}{9}(0) + \frac{1}{3} \][/tex]
Since any number multiplied by zero is zero, this simplifies to:
[tex]\[ f(0) = 0 + \frac{1}{3} = \frac{1}{3} \][/tex]
Therefore, the [tex]\( y \)[/tex]-intercept of the function [tex]\( f(x) = -\frac{2}{9} x + \frac{1}{3} \)[/tex] is [tex]\( \frac{1}{3} \)[/tex].
So, the correct answer is:
[tex]\(\boxed{\frac{1}{3}}\)[/tex]
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