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Sagot :
To determine the approximate cost of a train ticket for a 10-mile trip based on the line of best fit provided, we will use the given linear equation:
[tex]\[ y = 0.354x + 4.669 \][/tex]
Where [tex]\( y \)[/tex] represents the ticket cost in dollars and [tex]\( x \)[/tex] represents the distance traveled in miles. We need to calculate the ticket cost for [tex]\( x = 10 \)[/tex] miles.
Step-by-step solution:
1. Start with the given linear equation:
[tex]\[ y = 0.354x + 4.669 \][/tex]
2. Substitute the distance traveled ([tex]\( x = 10 \)[/tex]) into the equation:
[tex]\[ y = 0.354(10) + 4.669 \][/tex]
3. Perform the multiplication:
[tex]\[ y = 3.54 + 4.669 \][/tex]
4. Add the two numbers:
[tex]\[ y = 8.209 \][/tex]
Therefore, the approximate cost to ride the train for a distance of 10 miles is:
[tex]\[ \$ 8.21 \][/tex]
Thus, the correct answer is:
A. \$ 8.21
[tex]\[ y = 0.354x + 4.669 \][/tex]
Where [tex]\( y \)[/tex] represents the ticket cost in dollars and [tex]\( x \)[/tex] represents the distance traveled in miles. We need to calculate the ticket cost for [tex]\( x = 10 \)[/tex] miles.
Step-by-step solution:
1. Start with the given linear equation:
[tex]\[ y = 0.354x + 4.669 \][/tex]
2. Substitute the distance traveled ([tex]\( x = 10 \)[/tex]) into the equation:
[tex]\[ y = 0.354(10) + 4.669 \][/tex]
3. Perform the multiplication:
[tex]\[ y = 3.54 + 4.669 \][/tex]
4. Add the two numbers:
[tex]\[ y = 8.209 \][/tex]
Therefore, the approximate cost to ride the train for a distance of 10 miles is:
[tex]\[ \$ 8.21 \][/tex]
Thus, the correct answer is:
A. \$ 8.21
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