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What is the slope of the line with equation [tex] y - 3 = -\frac{1}{2}(x - 2) [/tex]?

A. [tex] -2 [/tex]
B. [tex] \frac{1}{2} [/tex]


Sagot :

To determine the slope of the given line equation [tex]\( y - 3 = -\frac{1}{2}(x - 2) \)[/tex], we need to rewrite it in the slope-intercept form [tex]\( y = mx + b \)[/tex], where [tex]\( m \)[/tex] represents the slope.

Let's simplify the given equation step-by-step:

1. Start with the given equation:
[tex]\[ y - 3 = -\frac{1}{2}(x - 2) \][/tex]

2. Distribute the [tex]\(-\frac{1}{2}\)[/tex] across the terms inside the parentheses:
[tex]\[ y - 3 = -\frac{1}{2} \cdot x + \left(-\frac{1}{2} \cdot -2 \right) \][/tex]
Simplify the multiplication inside the parentheses:
[tex]\[ y - 3 = -\frac{1}{2}x + 1 \][/tex]

3. Add 3 to both sides of the equation to isolate [tex]\( y \)[/tex]:
[tex]\[ y = -\frac{1}{2}x + 1 + 3 \][/tex]

4. Combine like terms on the right-hand side:
[tex]\[ y = -\frac{1}{2} x + 4 \][/tex]

Now that the equation is in the form [tex]\( y = mx + b \)[/tex], we can see that the coefficient of [tex]\( x \)[/tex] (the term [tex]\( m \)[/tex]) represents the slope of the line.

So, the slope [tex]\( m \)[/tex] is:
[tex]\[ m = -\frac{1}{2} \][/tex]

Thus, the slope of the line with the equation [tex]\( y - 3 = -\frac{1}{2}(x - 2) \)[/tex] is [tex]\( -\frac{1}{2} \)[/tex]. The correct answer is not included in the given choices.

Please check the problem conditions, as the correct slope [tex]\( -\frac{1}{2} \)[/tex] is not listed as [tex]\(-2\)[/tex] or [tex]\(\frac{1}{2}\)[/tex].