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Select the correct answer.

Which equation represents the horizontal line passing through [tex]\((-1, 2)\)[/tex]?

A. [tex]\(x = -1\)[/tex]
B. [tex]\(y = -1\)[/tex]
C. [tex]\(x = 2\)[/tex]
D. [tex]\(y = 2\)[/tex]


Sagot :

To determine the equation of the horizontal line passing through the point [tex]\((-1, 2)\)[/tex], we need to understand the characteristics of horizontal lines in a Cartesian plane.

### Characteristics of a horizontal line:
1. A horizontal line has a constant [tex]\(y\)[/tex]-value for all points along the line.
2. The [tex]\(y\)[/tex]-value of all the points on the line is equal to the [tex]\(y\)[/tex]-coordinate of the point through which the line passes.

Given the point [tex]\((-1, 2)\)[/tex], the [tex]\(y\)[/tex]-coordinate is 2. Therefore, the horizontal line passing through this point will have a constant [tex]\(y\)[/tex]-value of 2.

This can be expressed using the equation:
[tex]\[ y = 2 \][/tex]

Let's evaluate the given options to identify the correct answer:
- A. [tex]\(x = -1\)[/tex]: This represents a vertical line passing through [tex]\(x = -1\)[/tex], not a horizontal line.
- B. [tex]\(y = -1\)[/tex]: This represents a horizontal line, but it passes through a [tex]\(y\)[/tex]-coordinate of [tex]\(-1\)[/tex], which is incorrect.
- C. [tex]\(x = 2\)[/tex]: This represents a vertical line passing through [tex]\(x = 2\)[/tex], not a horizontal line.
- D. [tex]\(y = 2\)[/tex]: This represents a horizontal line passing through [tex]\(y = 2\)[/tex], which matches the requirement.

Hence, the correct equation that represents the horizontal line passing through the point [tex]\((-1, 2)\)[/tex] is:
[tex]\[ \boxed{y = 2} \][/tex]

So, the correct answer is:
[tex]\[ \text{D. } y = 2 \][/tex]