To solve the expression
[tex]\[ \frac{j^3 \cdot k}{h^0} \][/tex]
given the values [tex]\( h = 8 \)[/tex], [tex]\( j = -1 \)[/tex], and [tex]\( k = -12 \)[/tex], let's break it down step by step.
1. Evaluate [tex]\( h^0 \)[/tex]:
Any number raised to the power of 0 is equal to 1.
[tex]\[ h^0 = 8^0 = 1 \][/tex]
2. Calculate [tex]\( j^3 \)[/tex]:
[tex]\[ j = -1 \][/tex]
[tex]\[ j^3 = (-1)^3 = -1 \][/tex]
3. Multiply [tex]\( j^3 \)[/tex] by [tex]\( k \)[/tex]:
[tex]\[ j^3 \cdot k = -1 \cdot -12 = 12 \][/tex]
4. Divide by [tex]\( h^0 \)[/tex]:
Since [tex]\( h^0 = 1 \)[/tex],
[tex]\[ \frac{j^3 \cdot k}{h^0} = \frac{12}{1} = 12 \][/tex]
So, the value of the expression is:
[tex]\[ 12 \][/tex]
Therefore, the correct answer is:
[tex]\[ \boxed{12} \][/tex]
