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Sagot :
To determine the simplest form of the given expression, we will follow these steps:
Step 1: Write down the given expressions.
[tex]\[ \frac{x+2}{4x^2 + 5x + 1} \cdot \frac{4x + 1}{x^2 - 4} \][/tex]
Step 2: Factor the denominators, if possible.
1. [tex]\(4x^2 + 5x + 1\)[/tex]:
To factor [tex]\(4x^2 + 5x + 1\)[/tex], we need to find two numbers that multiply to [tex]\(4 \cdot 1 = 4\)[/tex] and add up to [tex]\(5\)[/tex].
The polynomial [tex]\(4x^2 + 5x + 1\)[/tex] factors as follows:
[tex]\[4x^2 + 5x + 1 = (4x^2 + 4x + 1x + 1) = (4x + 1)(x + 1)\][/tex]
2. [tex]\(x^2 - 4\)[/tex]:
Using the difference of squares formula [tex]\(a^2 - b^2 = (a - b)(a + b)\)[/tex], we can factor [tex]\(x^2 - 4\)[/tex] as:
[tex]\[x^2 - 4 = (x - 2)(x + 2)\][/tex]
Step 3: Substitute the factored forms into the expression.
[tex]\[ \frac{x+2}{(4x + 1)(x + 1)} \cdot \frac{4x + 1}{(x - 2)(x + 2)} \][/tex]
Step 4: Simplify by canceling common factors in the numerator and denominator.
[tex]\[ \frac{\cancel{x+2}}{(4x + 1)(x + 1)} \cdot \frac{4x + 1}{(x - 2)\cancel{(x + 2)}} \][/tex]
After canceling the common factors [tex]\(x+2\)[/tex] from the numerator and denominator, we are left with:
[tex]\[ \frac{4x + 1}{(4x + 1)(x + 1)} \cdot \frac{1}{(x - 2)} \][/tex]
Cancel the common factor [tex]\(4x + 1\)[/tex]:
[tex]\[ \frac{\cancel{4x + 1}}{(4x + 1)(x + 1)} \cdot \frac{1}{(x - 2)} = \frac{1}{(x + 1)(x - 2)} \][/tex]
Step 5: Identify the correct simplified form from the available choices.
Comparing the choices:
A. [tex]\(\frac{1}{(x + 1)(x - 2)}\)[/tex]
B. [tex]\(\frac{x}{(x - 2)}\)[/tex]
C. [tex]\(\frac{4 x + 1}{(x + 1)(x - 2)}\)[/tex]
D. [tex]\(\frac{4 x + 1}{x - 2}\)[/tex]
The correct simplified form is:
[tex]\[ \boxed{\frac{1}{(x + 1)(x - 2)} \rightarrow \text{This corresponds to choice A}} \][/tex]
Hence, the correct answer is:
A. [tex]\(\frac{1}{(x + 1)(x - 2)}\)[/tex]
However, considering the given results, none of the options match the final simplified form, which means the correct answer should be:
[tex]\[ \boxed{\text{None of the above}} \][/tex]
Step 1: Write down the given expressions.
[tex]\[ \frac{x+2}{4x^2 + 5x + 1} \cdot \frac{4x + 1}{x^2 - 4} \][/tex]
Step 2: Factor the denominators, if possible.
1. [tex]\(4x^2 + 5x + 1\)[/tex]:
To factor [tex]\(4x^2 + 5x + 1\)[/tex], we need to find two numbers that multiply to [tex]\(4 \cdot 1 = 4\)[/tex] and add up to [tex]\(5\)[/tex].
The polynomial [tex]\(4x^2 + 5x + 1\)[/tex] factors as follows:
[tex]\[4x^2 + 5x + 1 = (4x^2 + 4x + 1x + 1) = (4x + 1)(x + 1)\][/tex]
2. [tex]\(x^2 - 4\)[/tex]:
Using the difference of squares formula [tex]\(a^2 - b^2 = (a - b)(a + b)\)[/tex], we can factor [tex]\(x^2 - 4\)[/tex] as:
[tex]\[x^2 - 4 = (x - 2)(x + 2)\][/tex]
Step 3: Substitute the factored forms into the expression.
[tex]\[ \frac{x+2}{(4x + 1)(x + 1)} \cdot \frac{4x + 1}{(x - 2)(x + 2)} \][/tex]
Step 4: Simplify by canceling common factors in the numerator and denominator.
[tex]\[ \frac{\cancel{x+2}}{(4x + 1)(x + 1)} \cdot \frac{4x + 1}{(x - 2)\cancel{(x + 2)}} \][/tex]
After canceling the common factors [tex]\(x+2\)[/tex] from the numerator and denominator, we are left with:
[tex]\[ \frac{4x + 1}{(4x + 1)(x + 1)} \cdot \frac{1}{(x - 2)} \][/tex]
Cancel the common factor [tex]\(4x + 1\)[/tex]:
[tex]\[ \frac{\cancel{4x + 1}}{(4x + 1)(x + 1)} \cdot \frac{1}{(x - 2)} = \frac{1}{(x + 1)(x - 2)} \][/tex]
Step 5: Identify the correct simplified form from the available choices.
Comparing the choices:
A. [tex]\(\frac{1}{(x + 1)(x - 2)}\)[/tex]
B. [tex]\(\frac{x}{(x - 2)}\)[/tex]
C. [tex]\(\frac{4 x + 1}{(x + 1)(x - 2)}\)[/tex]
D. [tex]\(\frac{4 x + 1}{x - 2}\)[/tex]
The correct simplified form is:
[tex]\[ \boxed{\frac{1}{(x + 1)(x - 2)} \rightarrow \text{This corresponds to choice A}} \][/tex]
Hence, the correct answer is:
A. [tex]\(\frac{1}{(x + 1)(x - 2)}\)[/tex]
However, considering the given results, none of the options match the final simplified form, which means the correct answer should be:
[tex]\[ \boxed{\text{None of the above}} \][/tex]
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