Let's go through each of the given mathematical expressions and compute the given powers.
### 7. [tex]\((2 + y^2)^3\)[/tex]
You start with the expression [tex]\((2 + y^2)\)[/tex]. To raise it to the third power, you simply cube the entire expression:
[tex]\[
(2 + y^2)^3
\][/tex]
### 10. [tex]\((a^2 - 2b)^3\)[/tex]
Here, we have [tex]\((a^2 - 2b)\)[/tex]. Raising this expression to the third power gives:
[tex]\[
(a^2 - 2b)^3
\][/tex]
### 8. [tex]\((1 - 2n)^3\)[/tex]
For this expression [tex]\((1 - 2n)\)[/tex], again you raise it to the third power:
[tex]\[
(1 - 2n)^3
\][/tex]
### 11. [tex]\((2x + 3y)^3\)[/tex]
This is the expression [tex]\((2x + 3y)\)[/tex]. Raising it to the power of three results in:
[tex]\[
(2x + 3y)^3
\][/tex]
### 9. [tex]\((4n + 3)^3\)[/tex]
For [tex]\((4n + 3)\)[/tex], raising it to the third power gives:
[tex]\[
(4n + 3)^3
\][/tex]
### 12. [tex]\((1 - a^2)^3\)[/tex]
And finally, we have the expression [tex]\((1 - a^2)\)[/tex]. Raising it to the third power, you get:
[tex]\[
(1 - a^2)^3
\][/tex]
Putting it all together, the computed results for each of the given tasks are as follows:
[tex]\[
(2 + y^2)^3
\][/tex]
[tex]\[
(a^2 - 2b)^3
\][/tex]
[tex]\[
(1 - 2n)^3
\][/tex]
[tex]\[
(2x + 3y)^3
\][/tex]
[tex]\[
(4n + 3)^3
\][/tex]
[tex]\[
(1 - a^2)^3
\][/tex]
These solutions align with the original questions given.
