Engage with knowledgeable experts and get accurate answers on IDNLearn.com. Ask your questions and receive detailed and reliable answers from our experienced and knowledgeable community members.
Sagot :
Let's analyze the given problem step-by-step to find which values of [tex]\( b \)[/tex] make sense given the perimeter and the triangle inequality theorem.
1. We know the perimeter of the isosceles triangle is 15.7 inches. So, the equation for the perimeter is:
[tex]\[ 2a + b = 15.7 \][/tex]
2. Let's check each of the given possible values for [tex]\( b \)[/tex] and see if they fit the requirements.
3. The values given to check are:
[tex]\[ \{-2, 0, 0.5, 2, 7.9\} \][/tex]
### Checking Each Value:
- For [tex]\( b = -2 \)[/tex] inches:
[tex]\[ 2a - 2 = 15.7 \implies 2a = 17.7 \implies a = 8.85 \][/tex]
Given [tex]\( a = 8.85 \)[/tex] and [tex]\( b = -2 \)[/tex], [tex]\( b \)[/tex] cannot be negative for a triangle, so this value is not valid.
- For [tex]\( b = 0 \)[/tex] inches:
[tex]\[ 2a + 0 = 15.7 \implies 2a = 15.7 \implies a = 7.85 \][/tex]
Given [tex]\( a = 7.85 \)[/tex] and [tex]\( b = 0 \)[/tex], a side cannot be zero, so this value is not valid.
- For [tex]\( b = 0.5 \)[/tex] inches:
[tex]\[ 2a + 0.5 = 15.7 \implies 2a = 15.2 \implies a = 7.6 \][/tex]
Given [tex]\( a = 7.6 \)[/tex] and [tex]\( b = 0.5 \)[/tex]:
[tex]\[ 2a > b \implies 2 \cdot 7.6 > 0.5 \implies 15.2 > 0.5 \][/tex]
This is true, and since [tex]\( a \)[/tex] and [tex]\( b \)[/tex] are positive, this value is valid.
- For [tex]\( b = 2 \)[/tex] inches:
[tex]\[ 2a + 2 = 15.7 \implies 2a = 13.7 \implies a = 6.85 \][/tex]
Given [tex]\( a = 6.85 \)[/tex] and [tex]\( b = 2 \)[/tex]:
[tex]\[ 2a > b \implies 2 \cdot 6.85 > 2 \implies 13.7 > 2 \][/tex]
This is true, and since [tex]\( a \)[/tex] and [tex]\( b \)[/tex] are positive, this value is valid.
- For [tex]\( b = 7.9 \)[/tex] inches:
[tex]\[ 2a + 7.9 = 15.7 \implies 2a = 7.8 \implies a = 3.9 \][/tex]
Given [tex]\( a = 3.9 \)[/tex] and [tex]\( b = 7.9 \)[/tex]:
[tex]\[ 2a > b \implies 2 \cdot 3.9 > 7.9 \implies 7.8 \ngtr 7.9 \][/tex]
This does not satisfy the triangle inequality theorem, so this value is not valid.
### Conclusion:
The two values for [tex]\( b \)[/tex] that make sense given the perimeter and the rules of triangle formation are:
[tex]\[ \boxed{0.5 \text{ inches}, 2 \text{ inches}} \][/tex]
1. We know the perimeter of the isosceles triangle is 15.7 inches. So, the equation for the perimeter is:
[tex]\[ 2a + b = 15.7 \][/tex]
2. Let's check each of the given possible values for [tex]\( b \)[/tex] and see if they fit the requirements.
3. The values given to check are:
[tex]\[ \{-2, 0, 0.5, 2, 7.9\} \][/tex]
### Checking Each Value:
- For [tex]\( b = -2 \)[/tex] inches:
[tex]\[ 2a - 2 = 15.7 \implies 2a = 17.7 \implies a = 8.85 \][/tex]
Given [tex]\( a = 8.85 \)[/tex] and [tex]\( b = -2 \)[/tex], [tex]\( b \)[/tex] cannot be negative for a triangle, so this value is not valid.
- For [tex]\( b = 0 \)[/tex] inches:
[tex]\[ 2a + 0 = 15.7 \implies 2a = 15.7 \implies a = 7.85 \][/tex]
Given [tex]\( a = 7.85 \)[/tex] and [tex]\( b = 0 \)[/tex], a side cannot be zero, so this value is not valid.
- For [tex]\( b = 0.5 \)[/tex] inches:
[tex]\[ 2a + 0.5 = 15.7 \implies 2a = 15.2 \implies a = 7.6 \][/tex]
Given [tex]\( a = 7.6 \)[/tex] and [tex]\( b = 0.5 \)[/tex]:
[tex]\[ 2a > b \implies 2 \cdot 7.6 > 0.5 \implies 15.2 > 0.5 \][/tex]
This is true, and since [tex]\( a \)[/tex] and [tex]\( b \)[/tex] are positive, this value is valid.
- For [tex]\( b = 2 \)[/tex] inches:
[tex]\[ 2a + 2 = 15.7 \implies 2a = 13.7 \implies a = 6.85 \][/tex]
Given [tex]\( a = 6.85 \)[/tex] and [tex]\( b = 2 \)[/tex]:
[tex]\[ 2a > b \implies 2 \cdot 6.85 > 2 \implies 13.7 > 2 \][/tex]
This is true, and since [tex]\( a \)[/tex] and [tex]\( b \)[/tex] are positive, this value is valid.
- For [tex]\( b = 7.9 \)[/tex] inches:
[tex]\[ 2a + 7.9 = 15.7 \implies 2a = 7.8 \implies a = 3.9 \][/tex]
Given [tex]\( a = 3.9 \)[/tex] and [tex]\( b = 7.9 \)[/tex]:
[tex]\[ 2a > b \implies 2 \cdot 3.9 > 7.9 \implies 7.8 \ngtr 7.9 \][/tex]
This does not satisfy the triangle inequality theorem, so this value is not valid.
### Conclusion:
The two values for [tex]\( b \)[/tex] that make sense given the perimeter and the rules of triangle formation are:
[tex]\[ \boxed{0.5 \text{ inches}, 2 \text{ inches}} \][/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for choosing IDNLearn.com for your queries. We’re here to provide accurate answers, so visit us again soon.