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Sagot :
To determine the linear relationship [tex]\(y = mx + c\)[/tex] between [tex]\(x\)[/tex] and [tex]\(y\)[/tex] from the provided table, we follow these steps:
1. Plot the Points:
Let's plot the given points [tex]\((-3, -39)\)[/tex], [tex]\((-2, -29)\)[/tex], [tex]\((-1, -19)\)[/tex], [tex]\((0, -9)\)[/tex], [tex]\((1, 1)\)[/tex], and [tex]\((2, 11)\)[/tex] on the Cartesian plane.
2. Determine the Slope (m):
The slope [tex]\(m\)[/tex] of the linear equation [tex]\(y = mx + c\)[/tex] represents the steepness of the line. It can be calculated from the given points.
The slope [tex]\(m\)[/tex] is calculated as follows:
[tex]\[ m = \frac{\Delta y}{\Delta x} \][/tex]
Where [tex]\(\Delta y\)[/tex] is the change in [tex]\(y\)[/tex] values and [tex]\(\Delta x\)[/tex] is the change in [tex]\(x\)[/tex] values.
3. Calculate the Y-Intercept (c):
The y-intercept [tex]\(c\)[/tex] is the value of [tex]\(y\)[/tex] when [tex]\(x = 0\)[/tex].
Once computed, the linear equation [tex]\(y = mx + c\)[/tex] will describe the relation between [tex]\(x\)[/tex] and [tex]\(y\)[/tex].
From the table:
- When [tex]\(x = -3\)[/tex], [tex]\(y = -39\)[/tex]
- When [tex]\(x = -2\)[/tex], [tex]\(y = -29\)[/tex]
- When [tex]\(x = -1\)[/tex], [tex]\(y = -19\)[/tex]
- When [tex]\(x = 0\)[/tex], [tex]\(y = -9\)[/tex]
- When [tex]\(x = 1\)[/tex], [tex]\(y = 1\)[/tex]
- When [tex]\(x = 2\)[/tex], [tex]\(y = 11\)[/tex]
Upon calculating, we find:
- The slope [tex]\(m \approx 10.0\)[/tex]
- The y-intercept [tex]\(c \approx -9.0\)[/tex]
Thus, the linear equation describing the relationship is:
[tex]\[ y = 10x - 9 \][/tex]
To confirm, this means that for each unit increase in [tex]\(x\)[/tex], [tex]\(y\)[/tex] increases by approximately 10 units, and when [tex]\(x = 0\)[/tex], [tex]\(y \approx -9\)[/tex]. This relationship accurately fits the given data points. The polynomial equation in the standard form is:
[tex]\[ y = 10x - 9 \][/tex]
Therefore, the completed equation describing the relationship between [tex]\(x\)[/tex] and [tex]\(y\)[/tex] from the data provided is:
[tex]\[ y = 10x - 9 \][/tex]
1. Plot the Points:
Let's plot the given points [tex]\((-3, -39)\)[/tex], [tex]\((-2, -29)\)[/tex], [tex]\((-1, -19)\)[/tex], [tex]\((0, -9)\)[/tex], [tex]\((1, 1)\)[/tex], and [tex]\((2, 11)\)[/tex] on the Cartesian plane.
2. Determine the Slope (m):
The slope [tex]\(m\)[/tex] of the linear equation [tex]\(y = mx + c\)[/tex] represents the steepness of the line. It can be calculated from the given points.
The slope [tex]\(m\)[/tex] is calculated as follows:
[tex]\[ m = \frac{\Delta y}{\Delta x} \][/tex]
Where [tex]\(\Delta y\)[/tex] is the change in [tex]\(y\)[/tex] values and [tex]\(\Delta x\)[/tex] is the change in [tex]\(x\)[/tex] values.
3. Calculate the Y-Intercept (c):
The y-intercept [tex]\(c\)[/tex] is the value of [tex]\(y\)[/tex] when [tex]\(x = 0\)[/tex].
Once computed, the linear equation [tex]\(y = mx + c\)[/tex] will describe the relation between [tex]\(x\)[/tex] and [tex]\(y\)[/tex].
From the table:
- When [tex]\(x = -3\)[/tex], [tex]\(y = -39\)[/tex]
- When [tex]\(x = -2\)[/tex], [tex]\(y = -29\)[/tex]
- When [tex]\(x = -1\)[/tex], [tex]\(y = -19\)[/tex]
- When [tex]\(x = 0\)[/tex], [tex]\(y = -9\)[/tex]
- When [tex]\(x = 1\)[/tex], [tex]\(y = 1\)[/tex]
- When [tex]\(x = 2\)[/tex], [tex]\(y = 11\)[/tex]
Upon calculating, we find:
- The slope [tex]\(m \approx 10.0\)[/tex]
- The y-intercept [tex]\(c \approx -9.0\)[/tex]
Thus, the linear equation describing the relationship is:
[tex]\[ y = 10x - 9 \][/tex]
To confirm, this means that for each unit increase in [tex]\(x\)[/tex], [tex]\(y\)[/tex] increases by approximately 10 units, and when [tex]\(x = 0\)[/tex], [tex]\(y \approx -9\)[/tex]. This relationship accurately fits the given data points. The polynomial equation in the standard form is:
[tex]\[ y = 10x - 9 \][/tex]
Therefore, the completed equation describing the relationship between [tex]\(x\)[/tex] and [tex]\(y\)[/tex] from the data provided is:
[tex]\[ y = 10x - 9 \][/tex]
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