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Solve [tex]-6x + 3 \geq 21[/tex].

A. [tex]x \leq -3[/tex]
B. [tex]x \leq 3[/tex]
C. [tex]x \geq -3[/tex]
D. [tex]x \geq 3[/tex]


Sagot :

To solve the inequality [tex]\(-6x + 3 \geq 21\)[/tex], follow these steps:

1. Isolate the variable term:
[tex]\[ -6x + 3 \geq 21 \][/tex]
Subtract 3 from both sides of the inequality:
[tex]\[ -6x \geq 21 - 3 \][/tex]
Simplify the right side:
[tex]\[ -6x \geq 18 \][/tex]

2. Solve for [tex]\(x\)[/tex]:
To solve for [tex]\(x\)[/tex], divide both sides by [tex]\(-6\)[/tex]. Remember, when dividing or multiplying both sides of an inequality by a negative number, the inequality sign flips:
[tex]\[ x \leq \frac{18}{-6} \][/tex]
Simplify the fraction:
[tex]\[ x \leq -3 \][/tex]

Hence, the solution for the inequality [tex]\(-6x + 3 \geq 21\)[/tex] is [tex]\(x \leq -3\)[/tex].

Therefore, the correct answer is:
A. [tex]\(x \leq -3\)[/tex].