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The temperature is [tex]60^{\circ} F[/tex]. The temperature will decrease by [tex]3^{\circ} F[/tex] each hour. Let [tex]h[/tex] be the number of hours.

When will the temperature be below [tex]32^{\circ} F[/tex]?

Write an inequality for this problem.

A. [tex]60 - 3h \leq 32[/tex]
B. [tex]60 + 3h \ \textless \ 32[/tex]
C. [tex]60 + 3h \leq 32[/tex]
D. [tex]60 - 3h \ \textless \ 32[/tex]


Sagot :

Sure, let's work through the problem step-by-step.

1. Define the initial conditions and rate of change:
- The initial temperature is [tex]\(60^{\circ} F\)[/tex].
- The temperature decreases by [tex]\(3^{\circ} F\)[/tex] each hour.
- Let [tex]\(h\)[/tex] be the number of hours that have passed.

2. Set up the inequality:
- We need to find when the temperature will be below [tex]\(32^{\circ} F\)[/tex].
- The formula for the temperature after [tex]\(h\)[/tex] hours of decrease is:
[tex]\[ \text{Temperature after } h \text{ hours} = 60 - 3h \][/tex]
- We want this temperature to be below [tex]\(32^{\circ} F\)[/tex]:
[tex]\[ 60 - 3h < 32 \][/tex]

3. Solve the inequality:
- Start with the inequality:
[tex]\[ 60 - 3h < 32 \][/tex]
- Subtract 60 from both sides to isolate the term involving [tex]\(h\)[/tex]:
[tex]\[ -3h < 32 - 60 \][/tex]
[tex]\[ -3h < -28 \][/tex]
- Divide both sides by [tex]\(-3\)[/tex]. When dividing by a negative number, remember to reverse the inequality sign:
[tex]\[ h > \frac{-28}{-3} \][/tex]
[tex]\[ h > \frac{28}{3} \][/tex]
- Perform the division:
[tex]\[ h > 9.33 \][/tex]

So, the inequality that represents the time when the temperature will drop below [tex]\(32^{\circ} F\)[/tex] is:
[tex]\[ 60 - 3h < 32 \][/tex]

The correct answer from the options provided is:
D. [tex]\(60 - 3h < 32\)[/tex]