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Which value of [tex]$n$[/tex] would make the equations [tex]$4(0.5n - 3)$[/tex] and [tex]$n - 0.25(12 - 8n)$[/tex] equal to each other?

A. 3
B. [tex][tex]$-9$[/tex][/tex]
C. 0
D. [tex]$-15$[/tex]


Sagot :

To solve for the value of [tex]\( n \)[/tex] that makes the equations [tex]\( 4(0.5n - 3) \)[/tex] and [tex]\( n - 0.25(12 - 8n) \)[/tex] equal to each other, let's follow these steps:

1. Write down the equations:
[tex]\[ 4(0.5n - 3) \quad \text{and} \quad n - 0.25(12 - 8n) \][/tex]

2. Simplify each expression:

For the first expression:
[tex]\[ 4(0.5n - 3) = 4 \cdot 0.5n - 4 \cdot 3 = 2n - 12 \][/tex]

For the second expression:
[tex]\[ n - 0.25(12 - 8n) = n - 0.25 \cdot 12 + 0.25 \cdot 8n = n - 3 + 2n = 3n - 3 \][/tex]

3. Set the simplified expressions equal to each other:
[tex]\[ 2n - 12 = 3n - 3 \][/tex]

4. Solve for [tex]\( n \)[/tex]:

First, subtract [tex]\( 2n \)[/tex] from both sides:
[tex]\[ -12 = n - 3 \][/tex]

Next, add 3 to both sides:
[tex]\[ -12 + 3 = n \][/tex]

Simplifying the left-hand side:
[tex]\[ -9 = n \][/tex]

So, the value of [tex]\( n \)[/tex] that makes the two equations equal is [tex]\( n = -9 \)[/tex].

Thus, the answer is:
[tex]\[ \boxed{-9} \][/tex]