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Juliana had [tex]$\$[/tex]96[tex]$, which is eight times as much money as Al had. How much money did Al have? Select the correct solution method below, representing Al's money with $[/tex]x[tex]$.

A. $[/tex]x + 8 = 96[tex]$. Subtract 8 from both sides. Al had $[/tex]\[tex]$88$[/tex].
B. [tex]$\frac{x}{8} = 96$[/tex]. Multiply both sides by 8. Al had [tex]$\$[/tex]768[tex]$.
C. $[/tex]x - 8 = 96[tex]$. Add 8 to both sides. Al had $[/tex]\[tex]$104$[/tex].
D. [tex]$8x = 96$[/tex]. Divide both sides by 8. Al had [tex]$\$[/tex]12$.

Sagot :

GinnyAnsweridn
Let's look at the problem step by step. The problem says Juliana had \[tex]$96, which is eight times as much money as Al had. We're asked how much money Al had. Let's represent the amount of money Al had with \( x \). According to the problem: \[ 8x = 96 \] To find the value of \( x \), we need to solve this equation. We do this by dividing both sides of the equation by 8: \[ x = \frac{96}{8} \] When we perform the division: \[ x = 12 \] This means Al had \$[/tex]12.

Hence, the correct solution method is:

D. [tex]\( 8x = 96 \)[/tex]. Divide both sides by 8. Al had \$12.
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